使用NSKeyedUnarchiver unarchivedObject(ofClass:from :)取消存档数组

时间:2018-07-23 21:47:04

标签: ios swift nskeyedunarchiver ios12

自升级到Swift 4.2之后,我发现许多NSKeyedUnarchiver和NSKeyedArchiver方法已被弃用,我们现在必须使用类型方法static func unarchivedObject<DecodedObjectType>(ofClass: DecodedObjectType.Type, from: Data) -> DecodedObjectType?取消存档数据。

我已经成功地将定制类WidgetData的数组成功存档,该类是NSObject子类:

private static func archiveWidgetDataArray(widgetDataArray : [WidgetData]) -> NSData {

    guard let data = try? NSKeyedArchiver.archivedData(withRootObject: widgetDataArray as Array, requiringSecureCoding: false) as NSData
        else { fatalError("Can't encode data") }

    return data

}

当我尝试取消存档这些数据时出现问题:

static func loadWidgetDataArray() -> [WidgetData]? {

    if isKeyPresentInUserDefaults(key: USER_DEFAULTS_KEY_WIDGET_DATA) {

        if let unarchivedObject = UserDefaults.standard.object(forKey: USER_DEFAULTS_KEY_WIDGET_DATA) as? Data {

            //THIS FUNCTION HAS NOW BEEN DEPRECATED:
            //return NSKeyedUnarchiver.unarchiveObject(with: unarchivedObject as Data) as? [WidgetData]

            guard let nsArray = try? NSKeyedUnarchiver.unarchivedObject(ofClass: NSArray.self, from: unarchivedObject as Data) else {
                fatalError("loadWidgetDataArray - Can't encode data")
            }

            guard let array = nsArray as? Array<WidgetData> else {
                fatalError("loadWidgetDataArray - Can't get Array")
            }

            return array

        }

    }

    return nil

}

但这失败了,因为不允许使用Array.self而不是NSArray.self。我在做错什么,如何解决这个问题以取消存档?

6 个答案:

答案 0 :(得分:12)

您可以使用unarchiveTopLevelObjectWithData(_:)来取消存档archivedData(withRootObject:requiringSecureCoding:)存档的数据。 (我相信现在还不建议使用。)

但是在显示一些代码之前,您最好:

  • 避免使用NSData,而改用Data

  • 避免使用try?来处理对调试有用的错误信息

  • 删除所有不需要的演员


尝试一下:

private static func archiveWidgetDataArray(widgetDataArray : [WidgetData]) -> Data {
    do {
        let data = try NSKeyedArchiver.archivedData(withRootObject: widgetDataArray, requiringSecureCoding: false)

        return data
    } catch {
        fatalError("Can't encode data: \(error)")
    }

}

static func loadWidgetDataArray() -> [WidgetData]? {
    guard
        isKeyPresentInUserDefaults(key: USER_DEFAULTS_KEY_WIDGET_DATA), //<- Do you really need this line?
        let unarchivedObject = UserDefaults.standard.data(forKey: USER_DEFAULTS_KEY_WIDGET_DATA)
    else {
        return nil
    }
    do {
        guard let array = try NSKeyedUnarchiver.unarchiveTopLevelObjectWithData(unarchivedObject) as? [WidgetData] else {
            fatalError("loadWidgetDataArray - Can't get Array")
        }
        return array
    } catch {
        fatalError("loadWidgetDataArray - Can't encode data: \(error)")
    }
}

但是,如果要制作新应用,则最好考虑使用Codable

答案 1 :(得分:4)

unarchiveTopLevelObjectWithData(_:) 

也已弃用。因此,要在没有安全编码的情况下取消存档数据,您需要:

  1. 使用NSKeyedUnarchiver创建init(forReadingFrom: Data)
  2. 将创建的未存档的requiresSecureCoding设置为false。
  3. 调用decodeObject(of: [AnyClass]?, forKey: String) -> Any?来获取对象,只需使用适当的类并以NSKeyedArchiveRootObjectKey作为键即可。

答案 2 :(得分:2)

 if #available(iOS 12.0, *) {
        guard let unarchivedFavorites = try? NSKeyedUnarchiver.unarchiveTopLevelObjectWithData(favoritesData!)
            else {
                return
        }
        self.channelFavorites = unarchivedFavorites as! [ChannelFavorite]
    } else {
        if let unarchivedFavorites = NSKeyedUnarchiver.unarchiveObject(with: favoritesData!) as? [ChannelFavorite] {
            self.channelFavorites = unarchivedFavorites
        }

//获得数据

 if #available(iOS 12.0, *) {
            // use iOS 12-only feature
            do {
                let data = try NSKeyedArchiver.archivedData(withRootObject: channelFavorites, requiringSecureCoding: false)
                UserDefaults.standard.set(data, forKey: "channelFavorites")
            } catch {
                return
            }
        } else {
            // handle older versions
            let data = NSKeyedArchiver.archivedData(withRootObject: channelFavorites)
            UserDefaults.standard.set(data, forKey: "channelFavorites")
        }

这是我更新代码及其对我有用的方式

答案 3 :(得分:1)

您可能正在寻找:

if let widgetsData = UserDefaults.standard.data(forKey: USER_DEFAULTS_KEY_WIDGET_DATA) {
        if let widgets = (try? NSKeyedUnarchiver.unarchivedObject(ofClasses: [NSArray.self, WidgetData.self], from: widgetsData)) as? [WidgetData] {
            // your code
        }
    }

答案 4 :(得分:1)

Swift 5- IOS 13

guard let mainData = UserDefaults.standard.object(forKey: "eventDetail") as? NSData
else {
    print(" data not found in UserDefaults")
    return
}
do {
    guard let finalArray =
    try? NSKeyedUnarchiver.unarchiveTopLevelObjectWithData(mainData as Data) as? [EventDetail]
    else {
        return
    }
    self.eventDetail = finalArray
}

答案 5 :(得分:0)

由于iOS 14.3之后也不再推荐使用 unarchiveTopLevelObjectWithData ,因此现在只有Hopreeeenjust's answer是正确的。

但是,如果您不需要NSSecureCoding,也可以使用answer of Maciej S

通过向NSCoding协议添加扩展,非常容易使用它:

extension NSCoding where Self: NSObject {
    static func unsecureUnarchived(from data: Data) -> Self? {
        do {
            let unarchiver = try NSKeyedUnarchiver(forReadingFrom: data)
            unarchiver.requiresSecureCoding = false
            let obj = unarchiver.decodeObject(of: self, forKey: NSKeyedArchiveRootObjectKey)
            if let error = unarchiver.error {
                print("Error:\(error)")
            }
            return obj
        } catch {
            print("Error:\(error)")
        }
        return nil
    }
}

此扩展为取消存档,例如您只需要使用NSArray:

let myArray = NSArray.unsecureUnarchived(from: data)

对于Objective C,请使用NSObject类别:

+ (instancetype)unsecureUnarchivedFromData:(NSData *)data {
NSError * err = nil;
NSKeyedUnarchiver *unarchiver = [[NSKeyedUnarchiver alloc] initForReadingFromData: data error: &err];
unarchiver.requiresSecureCoding = NO;
id res = [unarchiver decodeObjectOfClass:self forKey:NSKeyedArchiveRootObjectKey];
err = err ?: unarchiver.error;
if (err != nil) {
    NSLog(@"NSKeyedUnarchiver unarchivedObject error: %@", err);
}
return  res;

}

请注意,如果requireSecureCoding为false,则实际上未检查未归档对象的类,即使从错误的类调用它,目标c代码也会返回有效结果。 从错误的类调用时,快速代码返回nil(由于可选的强制转换),但没有错误。