Question

这里我给定了json数据格式

var data = [Mon Jul 16 2018 21:54:14 GMT+0530 (India Standard Time), Mon Jul 16 2018 21:54:14 GMT+0530 (India Standard Time)]

以及如何将其转换为

classname(20180716,20180716)

我尝试使用split方法将数据转换为数组，但是我没有任何建议

我也遵循联接和拆分方法

function convert(str) {
    var date = new Date(str),
        mnth = ("0" + (date.getMonth()+1)).slice(-2),
        day  = ("0" + date.getDate()).slice(-2);
    return [ date.getFullYear(), mnth, day ].join("-");
}

convert("Thu Jun 09 2018 00:00:00 GMT+0530 (India Standard Time)");

Answer 1

按如下所示使用$refs：

    /// <summary>
    /// Use this extension method to update an observable collection without recreating it. This method keeps also track of the order items of the new collection.
    /// </summary>
    /// <remarks>This method was intended for short collection. The base complexity is around O(n+m) but the use of the IndexOf method make the complexity O(n*m)...O((n+m)*m).</remarks>
    /// <typeparam name="T"></typeparam>
    /// <param name="collection">The collection to update.</param>
    /// <param name="newCollection">The source of the new items.</param>
    public static void UpdateCollection<T>(this ObservableCollection<T> collection, IList<T> newCollection)
    {
        if ((null == newCollection) || (newCollection.Count == 0))
        {
            collection.Clear();
            return;
        }

        var i = 0;
        foreach (var it in newCollection)
        {
            if (collection.Count > i)
            {
                var itemIndex = collection.IndexOf(it);

                // This method would be match better, but it does not exist ;)
                //var remaining = list.Count - i;
                //itemIndex = list.IndexOf(it, i, remaining);

                if (itemIndex < 0)
                {
                    // this item was not found in the list
                    collection.Insert(i, it);
                }
                else if (itemIndex > i)
                {
                    // item is in the list but on a different place
                    collection.Move(itemIndex, i);
                }
                else
                {
                    // here the 'itemIndex' is less than or equal to 'i' --> we may have duplicate item 

                    // we check if the current items are the same!?
                    if (!EqualityComparer<T>.Default.Equals(collection[i], it))
                    {
                        // the items are different! The question is: do we need this item later?

                        // --> maybe: we keep (higher complexity)
                        collection.Insert(i, it);

                        // --> not: we can replace (lower complexity)
                        // list[i] = it;

                    }
                    else
                    {
                        // yop: the items are the same, we do nothing.
                    }
                }
            }
            else
            {
                // add new item
                collection.Add(it);
            }

            i++;
        }

        // we remove the remaining items.
        while (collection.Count > newCollection.Count) {
            collection.RemoveAt(i);
        };
    }

使用分号分隔行对我有用：

<input type="button" value="Sign On" class="ButtonSm" onclick="submitForm();">

关键是分别声明Dim IE Set IE = CreateObject("InternetExplorer.Application") IE.Visible = 1 IE.navigate "www.xxx.com" Do While (IE.Busy) Application.Wait DateAdd("s", 1, Now) Loop With IE.Document .getElementByID("USER").Value = UserName .getElementByID("PASSWORD").Value = Password .getElementByClassName("ButtonSm").Click End With End Sub。

输出：

data

要处理所有日期的数组：

var data = [
  "Mon Jul 16 2018 21:54:14 GMT+0530 (India Standard Time)",
  "Mon Jul 16 2018 21:54:14 GMT+0530 (India Standard Time)"
];

还请注意，function convert(str) { var date = new Date(str); var mnth = ("0" + (date.getMonth() + 1)).slice(-2); var day = ("0" + date.getDate()).slice(-2); return [date.getFullYear(), mnth, day].join("-"); } console.log(convert("Thu Jun 09 2018 00:00:00 GMT+0530 (India Standard Time)"));应该包含字符串数组。

无法将日期格式转换为2018年7月23日星期一21:54:14 GMT + 0530（印度标准时间）为YYYYMMDD

1 个答案: