我正在尝试为Spring Boot应用程序创建前端,我选择了React,但是我对React或JavaScript没有太多的经验。 因此,我有一个要用于发送帖子请求的表单,但是当我按下“提交”按钮时,似乎什么也没发生。我假设这是我的onSubmit处理程序,但是我不知道这有什么问题。当我手动发送POST请求时,它可以正常工作,因此我认为不是REST API引起了问题。
import React, { Component } from 'react';
import ReactDOM from 'react-dom';
import axios from 'axios';
import { Link } from 'react-router-dom';
class Create extends Component {
constructor() {
super();
this.state = {
name: '',
email: '',
title: '',
description: ''
};
}
onChange = (e) => {
const state = this.state
state[e.target.name] = e.target.value;
this.setState(state);
}
onSubmit = (e) => {
e.preventDefault();
const { name, email, title, description } = this.state;
axios.post('/create', { name, email, title, description })
.then((result) => {
this.props.history.push("/")
});
}
render() {
const { name, email, title, description } = this.state;
return (
<div class="container">
<div class="panel panel-default">
<div class="panel-heading">
<h3 class="panel-title">
Send Message
</h3>
</div>
<div class="panel-body">
<h4><Link to="/"><span class="glyphicon glyphicon-th-list" aria-hidden="true"></span> Message List</Link></h4>
<form onSubmit={this.onSubmit}>
<div class="form-group">
<label for="name">Name:</label>
<input type="text" class="form-control" name="name" onChange={this.onChange}/>
</div>
<div class="form-group">
<label for="email">Email:</label>
<input type="text" class="form-control" name="email" onChange={this.onChange}/>
</div>
<div class="form-group">
<label for="title">Title:</label>
<input type="text" class="form-control" name="title" onChange={this.onChange}/>
</div>
<div class="form-group">
<label for="description">Description:</label>
<input type="text" class="form-control" name="description" onChange={this.onChange}/>
</div>
<button type="submit" class="btn btn-default">Submit</button>
</form>
</div>
</div>
</div>
);
}
}
export default Create;
答案 0 :(得分:1)
React的第一条规则是,您不直接更新state属性(否则React不会知道状态已更改)。
要知道React的表现并不容易。
因此,与其直接设置状态值,不如
onChange = (e) => {
const state = this.state
state[e.target.name] = e.target.value;
this.setState(state);
}
像这样更改它,然后尝试再次提交。
onChange = (e) => {
const state = this.state
this.setState({[e.target.name]: e.target.value});
}