Question

我有如下所示的数据示例，我想提取具有键/值模式的数据，例如：

'Signature Algorithm: ecdsa-with-SHA256', 'Not Before: Jul 23 00:00:00 2018 GMT', 'Not After : Jul 19 00:00:00 2033 GMT, 'Public Key Algorithm: id-ecPublicKeyid', Public-Key: (256 bit)'

示例：

['Certificate:', 'Data:', 'Version: 3 (0x2)', 'Serial Number:', 'b9:d9:f5:38:f8:42:6a:f9', 'Signature Algorithm: ecdsa-with-SHA256', 'Issuer: C=US, ST=NC, L=Raleigh, O=Eaton Corporation, OU=Electrical Division, CN=PowerXpert-02-00-34-56-63-01', 'Validity', 'Not Before: Jul 23 00:00:00 2018 GMT', 'Not After : Jul 19 00:00:00 2033 GMT', 'Subject: C=US, ST=NC, L=Raleigh, O=Eaton Corporation, OU=Electrical Division, CN=PowerXpert-02-00-34-56-63-01', 'Subject Public Key Info:', 'Public Key Algorithm: id-ecPublicKey', 'Public-Key: (256 bit)', 'pub:', '04:bf:72:4b:01:8b:5c:46:98:96:a6:d6:06:7b:d8:', '73:50:2f:47:85:60:f0:38:25:79:3d:96:be:20:3b:', '3f:39:c8:58:62:e9:d7:b6:f8:3a:6b:24:50:e1:5c:', '78:ce:5e:28:f2:60:3a:b6:cc:43:0e:0b:2b:d6:03:', '51:76:21:a4:78', 'ASN1 OID: prime256v1', 'NIST CURVE: P-256', 'X509v3 extensions:', 'X509v3 Subject Key Identifier:', '6A:E0:28:A7:17:2B:65:01:FD:31:48:5C:68:24:94:4B:42:49:76:58', 'X509v3 Basic Constraints: critical', 'CA:TRUE', 'X509v3 Key Usage: critical', 'Digital Signature, Certificate Sign, CRL Sign', 'X509v3 Subject Alternative Name:', 'DNS:PXG900-56-63-01', 'Signature Algorithm: ecdsa-with-SHA256', '30:45:02:20:43:33:58:ce:ef:f7:fd:a8:60:21:15:a3:2b:35:', '8c:1f:13:a0:1e:77:05:6f:1a:bb:a0:b6:fe:f3:ea:7b:6d:31:', '02:21:00:cf:db:9a:d1:6b:88:ae:fb:d5:5c:5a:db:0a:a0:eb:', 'a9:c9:4a:52:d0:57:18:9c:58:1b:67:42:47:c5:ec:bf:b0', '', '']

在正则表达式下使用，但未获得预期的结果

regex = re.compile(r'''
[\S]+:                # a key (any word followed by a colon)
(?:
\s                    # then a space in between
(?!\S+:)\S+           # then a value (any word not followed by a colon)
)+                    # match multiple values if present
''', re.VERBOSE)

matches = regex.findall(str(lines))
print(matches)

Answer 1

您可以使用以下正则表达式：

kernel matrix which as stated before is the null(A), must be 10x10

(?='[A-Za-z]+[\s-][A-Z][a-z]+\s?:?)'[^']+:[^']+'正向前进。断言以下是：
- (?=，撇号'[A-Za-z]+，后跟字母字符。
- '的空白或破折号[\s-]。
- -字母字符。
- [A-Za-z]+可选空格。
- \s?可选冒号:?\s，后跟空白。
:近距离搜索。
)匹配撇号'[^']+字符，而不是撇号'字符的任何字符。
'匹配一个冒号。
:匹配所有非撇号[^']+'的字符，后跟撇号'。

您可以实时测试正则表达式here。

Python代码段：

输出：

import re
lines = ['Certificate:', 'Data:', 'Version: 3 (0x2)', 'Serial Number:', 'b9:d9:f5:38:f8:42:6a:f9', 'Signature Algorithm: ecdsa-with-SHA256', 'Issuer: C=US, ST=NC, L=Raleigh, O=Eaton Corporation, OU=Electrical Division, CN=PowerXpert-02-00-34-56-63-01', 'Validity', 'Not Before: Jul 23 00:00:00 2018 GMT', 'Not After : Jul 19 00:00:00 2033 GMT','Public Key Algorithm: id-ecPublicKey',
'Public-Key: (256 bit)']
matches = re.findall(r"(?='[A-Za-z]+[\s-][A-Z][a-z]+\s?:?)'[^']+:[^']+'",str(lines))
for match in matches:
    print (match)

Answer 2

我不确定我是否完全理解。但是你不能走吗？

extracted = []
for item in lines:
    if len(item.split(": ")) == 2: # It has 2 items
        extracted.append(item)

这将提取每个在“：”两边带有“东西”的项目。我希望这会有所帮助。

Answer 3

您可以使用此正则表达式提取键值对。

([a-zA-Z0-9 ]*:[a-zA-Z0-9\- :]*)

Demo Link

Answer 4

 re.findall("'[A-Z][^':]+:[^',:]+(?:\d{2}:){0,3}[^',:]+'(?=,)",str(lines))
Out[139]: 
["'Version: 3 (0x2)'",
 "'Signature Algorithm: ecdsa-with-SHA256'",
 "'Not Before: Jul 23 00:00:00 2018 GMT'",
 "'Not After : Jul 19 00:00:00 2033 GMT'",
 "'Public Key Algorithm: id-ecPublicKey'",
 "'Public-Key: (256 bit)'",
 "'ASN1 OID: prime256v1'",
 "'NIST CURVE: P-256'",
 "'X509v3 Basic Constraints: critical'",
 "'CA:TRUE'",
 "'X509v3 Key Usage: critical'",
 "'DNS:PXG900-56-63-01'",
 "'Signature Algorithm: ecdsa-with-SHA256'"]

需要帮助从列表中提取数据模式，如下所示

4 个答案: