Question

<app:service xmlns:app="http://www.w3.org/2007/app"...>
 <app:workspace>
   <atom:title type="text">Data</atom:title>
  <app:collection . . .>
   <atom:title type="text">CourseContentSet</atom:title>
   <demo:member-title>CourseContent</demo:member-title>
  </app:collection>
  <app:collection . . .>
   <atom:title type="text">UnitContentSet</atom:title>
   <demo:member-title>UnitContent</demo:member-title>
  </app:collection>
 </app:workspace>
</app:service>

我如何获得demo：member-title？

我尝试这样做，但没有成功...

         soapDatainJsonObject = XML.toJSONObject(soapmessageString);
        JSONObjectsongs=soapDatainJsonObject.getJSONObject("app:service");  
            JSONObject songs2 = songs.getJSONObject("app:workspace");
            String content = songs2.getString("app:collection")
            System.out.println(content);

我如何访问XML文件的内部？通过JSON。我想获取CourseContent，UnitContent..etc

Answer 1

您需要解析每个深度。试试这个：

JSONObject soapDatainJsonObject = XML.toJSONObject(soapmessageString);
    JSONObject songs= soapDatainJsonObject.getJSONObject("app:service");
    JSONObject songs2 = songs.getJSONObject("app:workspace");
    JSONArray atomArray =  songs2.getJSONArray("app:collection");
    JSONObject atomTitle = atomArray.getJSONObject(0).getJSONObject("atom:title");
    String content = atomTitle.getString("content");
    System.out.println(content);

获取JSON对象（XML类型）的特定对象

1 个答案: