我正在尝试将一个大小为300MB的zip文件（主要包含python软件包）上传到AWS Lambda。我清楚地了解，如果我们直接使用AWS开发工具包上传，则超出了可以上传到Lambda的zip的限制。因此，这将不起作用。
为了克服这个问题，我决定将软件包下载到cout << endl;目录中，并将其导入到主文件中（参考文献here）。我将所需的软件包压缩为for并将其上传到AWS S3。然后我使用int main()
{
int n, t1 = 0, t2 = 1,t3 = 2, nextTerm = 0;
cout << "Enter the number of terms: "; cin >> n;
cout << "Fibonacci number sequence up to " << n << ":" << endl;
for (int i = 1; i <= n+1; i++)
{
if (i == 1)
{
cout << " " << t1;
continue;
}
if (i == 2)
{
cout << " " << t2 << " ";
continue;
}
nextTerm = t1 + t2;
t1 = t2;
t2 = nextTerm;
cout << nextTerm << "";
}
cout << endl;
cout << "Number of times iterative function is called: " << n * 3 << endl;
return 0;
下载它们，将它们提取到/tmp。
pkgs.zip但是，当我测试lambda函数时，它返回一个错误，提示找不到requests
/tmp/
我的问题是，如何从def get_pkgs(url):
import requests
import io
import zipfile
print("Getting Packages...")
re = requests.get(url)
z = zipfile.ZipFile(io.BytesIO(re.content))
print("Extracting Packages...")
z.extractall("/tmp/")
print("Packages are downloaded and extracted.")
def attempt_import():
print("="*50)
print("ATTEMPT TO IMPORT DEPENDENCIES...")
print("="*50)
import numpy
import scipy
import six
print("IMPORTING DONE.")
def main():
URL = "https://s3-ap-southeast-1.amazonaws.com/BUCKET_NAME/pkgs.zip"
get_pkgs(URL)
attempt_import()
def lambda_handler(event, context):
main()
return "Hello Lambda"
目录中导入所需的软件包？
谢谢。
答案 0 :(得分：0)
在将任何已下载的软件包导入到/tmp文件夹（例如，到/tmp/requirements文件夹）之前，必须告诉系统在那寻找依赖项。在代码的开头，仅在以下几行：
import sys
sys.path.insert(0, '/tmp/requirements/') # Or any path you desire