如何通过DFC代码获取当前版本的标签号?

时间:2018-07-23 04:39:20

标签: version-control version ecm dfc documentum-dfc

public static IDfCollection getVersions() {
    IDfQuery query = clientX.getQuery();// obtain an idfObject
    query.setDQL(
            "select r_object_id,object_name,r_version_label,owner_name from dm_document(all) where i_chronicle_id='090008868006d5be'");
    IDfCollection collection = null;
    try {
        collection = query.execute(SessionFile.getSession(), IDfQuery.DF_READ_QUERY);
    } catch (DfException e) {
        e.printStackTrace();
    }
    return collection;

}

public class Versions {
public static void main(String[] args) {
    IDfCollection collection = AllOperations.getVersions();
    try {
        int versionsCount = collection.getValueCount("r_object_id");
        //IDfSysObject dfSysObject=(IDfSysObject) SessionFile.getSession().getObject(new DfId("09000886800a143e"));
        while (collection.next()) {
            //String versionNum = dfSysObject.getVersionLabels().getImplicitVersionLabel();
            int i = 0;
            while (i < versionsCount) {
                System.out.println(collection.getRepeatingValue("r_version_label", i));
                i++;
            }
        }
    } catch (DfException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

}

  

以上代码的输出为:   1.0,   1.1,   1.2,   当前

enter image description here

我要代替“ CURRENT”标签,“获取版本号”,例如2.0或3.0等,这是最新的文档版本号。

需要如下所示的输出:

enter image description here

1 个答案:

答案 0 :(得分:1)

首先,这一行:

int versionsCount = collection.getValueCount("r_object_id");

应该是

int versionsCount = collection.getValueCount("r_version_label");

,并且必须在while(collection.next())循环中,这样,它将正确地迭代所有r_version_label值,因此代码现在将输出:

1.0
1.1
1.2 
CURRENT
2.0

您现在可以摆脱CURRENT(或者通常摆脱所有无法解析为浮点数的非值)。