第一个问题
我运行了这个简单的代码,将行数据转置为列,但只显示了第一个数据。为什么会发生?
SELECT
id_material,
at_part_number,
mat_desc,
GROUP_CONCAT(equipment_name SEPARATOR ', ') As Equipment`
FROM material
INNER JOIN equipment_list ON material.id_material=equipment_list.PKid_material
INNER JOIN equipment ON equipment_list.PKid_equipment=equipment.id_equipment;
然后如何使“设备1”,“设备2”,“ Equipmnet 3” ...列?不是由SEPARATOR而是在创建一些新列?
--------------------------------------------------+
| id_material | mat_part_number | Equipment
+----------------------------------------------------+
| 1000001 | AA111 | eq1, eq2, eq3 |
+-----------------------------------------------------+
第二个问题
SELECT
id_material,
mat_part_number,
mat_desc,`
GROUP_CONCAT(equipment_name SEPARATOR ', ') As Equipment
FROM material
INNER JOIN equipment_list ON material.id_material=equipment_list.PKid_material INNER JOIN equipment ON equipment_list.PKid_equipment=equipment.id_equipment;
UNION
SELECT
id_material,
alt_part_number,
mat_desc,
GROUP_CONCAT(equipment_name SEPARATOR ', ') As Equipment
FROM material
INNER JOIN equipment_list ON material.id_material=equipment_list.PKid_material
INNER JOIN equipment ON equipment_list.PKid_equipment=equipment.id_equipment
INNER JOIN alternatif_list ONmaterial.id_material=alternatif_list.PKid_material
INNER JOIN alternatif ON alternatif.id_alternatif=alternatif_list.PKid_alternatif
ORDER BY
id_material asc;
注意:物料表是父表,物料表和设备表具有多对多关系,因此物料表和交替表也是如此。 1个材料可以包括2个设备,2个交替设备(等同于交替设备的材料设备)
我要做这个
`---------------------------------------------------------------------------`
`id_material | part_number | equipment (1) | equipment (2) | equipment (n) |`
`---------------------------------------------------------------------------`
`100001 | AA111 | nameeq1 |nameeq2 |`
`100001 | AA112 | nameeq1 |nameeq2 |` //alternatif part_number
`100002 | AA222 | nameeq3 | |`
`100002 | AA221 | nameeq3 | |` //alternatif part_number
`100003 | AA333 | nameeq4 |nameeq5 |`
`100003 | AA331 | nameeq4 |nameeq5 |` //alternatif part_number
答案 0 :(得分:0)
给出这么简单的数据
DROP TABLE IF EXISTS T;
CREATE TABLE T (ID INT,col1 varchar(3));
insert into t values (1,'aaa'),(1,'bbb'),(2,'aaa'),(3,'aaa'),(3,'bbb'),(3,'ccc');
如果您group_concat没有分组依据
select id,group_concat(col1)
from t;
你明白了
+------+-------------------------+
| id | group_concat(col1) |
+------+-------------------------+
| 1 | aaa,bbb,aaa,aaa,bbb,ccc |
+------+-------------------------+
1 row in set (0.00 sec)
分组依据
select id,group_concat(col1)
from t
group by id;
你明白了
+------+--------------------+
| id | group_concat(col1) |
+------+--------------------+
| 1 | aaa,bbb |
| 2 | aaa |
| 3 | aaa,bbb,ccc |
+------+--------------------+
3 rows in set (0.00 sec)
如果您希望使用单独的列并具有有限数量的值,则可以使用条件聚合
select id,
max(case when col1 = 'aaa' then col1 else '' end) as first,
max(case when col1 = 'bbb' then col1 else '' end) as second,
max(case when col1 = 'ccc' then col1 else '' end) as third
from t
group by id;
得到这个
+------+-------+--------+-------+
| id | first | second | third |
+------+-------+--------+-------+
| 1 | aaa | bbb | |
| 2 | aaa | | |
| 3 | aaa | bbb | ccc |
+------+-------+--------+-------+
3 rows in set (0.00 sec)
如果您不知道这些值或它们可能会发生变化,则可以构建一个sql语句并将其提交给动态sql
set @sql = (
select group_concat(concat('max(case when col1 = ', char(39),s.val,char(39),' then col1 else null end) as ', val))
from
(select distinct col1 as val from t order by col1) s
)
;
set @sql = concat('select id,', @sql,' from t group by id;');
prepare sqlstmt from @sql;
execute sqlstmt;
deallocate prepare sqlstmt;
返回此
+------+------+------+------+
| id | aaa | bbb | ccc |
+------+------+------+------+
| 1 | aaa | bbb | NULL |
| 2 | aaa | NULL | NULL |
| 3 | aaa | bbb | ccc |
+------+------+------+------+
3 rows in set (0.00 sec)
如果要限制列数,则使用变量来计算最大列数如下所示:
DROP TABLE IF EXISTS T;
CREATE TABLE T (ID INT,col1 varchar(3));
insert into t values (1,'aaa'),(1,'bbb'),(2,'aaa'),(3,'aaa'),(3,'ddd'),(3,'eee');
set @sql = (
select group_concat(distinct concat('max(case when s.rn = ', S.RN,' then col1 else null end) as Equipment_', S.RN))
from
(
SELECT ID,
IF(ID <> @P, @RN:=1,@RN:=@RN+1) RN,
@P:=ID P
FROM T
CROSS JOIN (SELECT @RN:=0,@P:=0) R
) S
);
set @sql = concat('select id,', @sql,' from
(
SELECT ID,col1,
IF(ID <> @P, @RN:=1,@RN:=@RN+1) RN,
@P:=ID P
FROM T
CROSS JOIN (SELECT @RN:=0,@P:=0) R
order by id,col1
) S group by id;');
#SELECT @SQL;
prepare sqlstmt from @sql;
execute sqlstmt;
deallocate prepare sqlstmt;
+------+-------------+-------------+-------------+
| id | Equipment_1 | Equipment_2 | Equipment_3 |
+------+-------------+-------------+-------------+
| 1 | aaa | bbb | NULL |
| 2 | aaa | NULL | NULL |
| 3 | aaa | ddd | eee |
+------+-------------+-------------+-------------+
3 rows in set (0.00 sec)