Question

当我使用时：

    WorkManagerTestInitHelper.initializeTestWorkManager(context);
    WorkManager workManager =  WorkManager.getInstance();

要获取WorkManager实例，WorkManager无法实现重试。我将提出最简单的测试：

public class WorkManagerTest {



   Context context;


@Before
public void setUp() throws Exception {

    context = InstrumentationRegistry.getTargetContext();


}






@Test
public   void testWorker1(){
    Constraints constraints = new Constraints.Builder()
                .build();
    OneTimeWorkRequest.Builder updateorderworkerBuilder =
            new OneTimeWorkRequest.Builder(TestWorker1.class)
                    .setConstraints(constraints)
                    //MIN_BACKOFF_MILLIS == 10000
                    .setBackoffCriteria(BackoffPolicy.LINEAR,10000, TimeUnit.MILLISECONDS);




    OneTimeWorkRequest workRequest = updateorderworkerBuilder.build();
    WorkManager workManager =  WorkManager.getInstance();
    workManager.enqueue(workRequest);

    try {
        Thread.sleep(50000);
    } catch (InterruptedException e) {
        e.printStackTrace();
    }


}


@Test
public   void testWorker2(){
    Constraints constraints = new Constraints.Builder()
                           .build();
    OneTimeWorkRequest.Builder updateorderworkerBuilder =
            new OneTimeWorkRequest.Builder(TestWorker2.class)
                    .setConstraints(constraints)
                    //MIN_BACKOFF_MILLIS == 10000
                    .setBackoffCriteria(BackoffPolicy.LINEAR,10000, TimeUnit.MILLISECONDS);




    OneTimeWorkRequest workRequest = updateorderworkerBuilder.build();
    WorkManagerTestInitHelper.initializeTestWorkManager(context);
    WorkManager workManager =  WorkManager.getInstance();
    workManager.enqueue(workRequest);

    try {
        Thread.sleep(50000);
    } catch (InterruptedException e) {
        e.printStackTrace();
    }


}


public static class TestWorker1 extends Worker {

    /**
     * Override this method to do your actual background processing.
     *
     * @return The result of the work, corresponding to a {@link Result} value.  If a
     * different value is returned, the result shall be defaulted to
     * {@link Result#FAILURE}.
     */
    @NonNull
    @Override
    public Result doWork() {
        Log.d("TEST_WORKER", "inside doWork()1");
        return Result.RETRY;
    }
}


public static class TestWorker2 extends Worker {

    /**
     * Override this method to do your actual background processing.
     *
     * @return The result of the work, corresponding to a {@link Result} value.  If a
     * different value is returned, the result shall be defaulted to
     * {@link Result#FAILURE}.
     */
    @NonNull
    @Override
    public Result doWork() {
        Log.d("TEST_WORKER", "inside doWork()2");
        return Result.RETRY;
    }
}

}

在Logcat中，我看到：

07-22 23:34:25.184 5346-5388/com.billst.app.debug D/TEST_WORKER: inside doWork()1
07-22 23:34:30.178 5346-5391/com.billst.app.debug D/TEST_WORKER: inside doWork()1
07-22 23:34:40.238 5346-5388/com.billst.app.debug D/TEST_WORKER: inside doWork()1
07-22 23:35:00.300 5346-5391/com.billst.app.debug D/TEST_WORKER: inside doWork()1
07-22 23:35:15.130 5346-5372/com.billst.app.debug D/TEST_WORKER: inside doWork()2

即使我独立执行2个测试，我也会得到相同的结果。我们看到使用 WorkManagerTestInitHelper 会阻止WorkManager完成工作重试。

我是否正确使用 WorkManagerTestInitHelper ？

Answer 1

您不能在测试模式下模拟重试。这是有意的，因为您应该测试Worker而不是测试WorkManager。您不能为此使用WorkManagerTestInitHelper。如果要测试Worker返回的Result.retry()，那么还可以使用新的TestWorkerBuilder<>和TestListenableWorkerBuilder API。

这里是一个例子。 https://android.googlesource.com/platform/frameworks/support/+/androidx-master-dev/work/workmanager-testing/src/androidTest/java/androidx/work/testing/TestWorkerBuilderTest.kt

使用WorkManagerTestInitHelper会阻止WorkManager完成工作的重试

1 个答案: