如何将多行转换为多列?

时间:2018-07-22 21:11:35

标签: sql oracle oracle11g pivot

将seq列的升值中的col_1分组以显示以下示例数据的多列中的注释列中的值:

col_1  |  Seq  |  Comment |
--------------------------|
ABC    |   30  |  TestC   |
ABC    |   50  |  TestE   |
ABC    |   80  |  TestG   |
ABC    |   10  |  TestA   |
ABC    |   60  |  TestF   |
ABC    |   20  |  TestB   |
ABC    |   70  |  TestF   |
ABC    |   40  |  TestD   |
DEF    |   20  |  TestB   |
DEF    |   10  |  TestA   |
GHI    |   10  |  TestA   |
--------------------------|

Expected output of sql should be:
Col_1  | Col_2 | Col_3 | Col_4 | Col_5 | Col_6 | Col_7 | Col_8 | 
-------|-------|-------|-------|-------|-------|-------|-------|
ABC    | TestA | TestB | TestC | TestD | TestE | TestF | TestG |
DEF    | TestA | TestB |       |       |       |       |       |
GHI    | TestA |       |       |       |       |       |       |
-------|-------|-------|-------|-------|-------|-------|-------|

2 个答案:

答案 0 :(得分:1)

您可以使用条件聚合和row_number()

select col_1,
       max(case when seqnum = 1 then comment end) as col_2,
       max(case when seqnum = 2 then comment end) as col_3,
       max(case when seqnum = 3 then comment end) as col_4,
       . . .
from (select t.*,
             row_number() over (partition by col_1 order by seq) as seqnum
      from t
     ) t
group by col_1;

答案 1 :(得分:0)

这基本上使用了Gordon的答案中相同的row_number函数,但使用了PIVOT子句。

SELECT *
FROM (
    SELECT t.COL_1
        ,t.comments
        ,row_number() OVER (
            PARTITION BY col_1 ORDER BY seq
            ) AS seqnum
    FROM t
    ) t
PIVOT(MAX(comments) FOR seqnum IN (1 as col_2,2 as col_3,3 as col_4,
                                   4 as col_5,5 as col_6,6 as col_7,
                                   8 as col_8));

Demo