PHP / HTML查询字符串从URL链接中删除

Question

我正在尝试传递包含完整网址的链接；

http://xxx.co.uk/trackit.php?page=http://xxx.co.uk/game?p=buildings&menu

正如您在上面的链接中看到的那样，首先进入一个名为trackit的脚本，进行一些跟踪，然后重定向到我想要的实际页面，但是在这种情况下，“＆menu”被删除了，我想我理解为什么，但无法修复。

$next_page = mysqli_real_escape_string($con, $_GET['page']);
header("Location: $next_page");

任何建议都会很棒。 谢谢

Answer 1

//before display your url
$page = urlencode('http://xxx.co.uk/game?p=buildings&menu');
$url = 'http://xxx.co.uk/trackit.php?page=' . $page;

echo $url;
// displays
// http://xxx.co.uk/trackit.php?page=http%3A%2F%2Fxxx.co.uk%2Fgame%3Fp%3Dbuildings%26menu


//when you receive it on the get
$next_page = urldecode($_GET['page']);
header("Location: $next_page");