我这里有以下数据集
http://sqlfiddle.com/#!17/70f9a/1
我想创建一个查询,结果如下:
这个想法只是以不同的方式(jsonb值)重新显示cols avg_time_1和avg_time_2值
答案 0 :(得分:1)
使用jsonb_build_object()
构建主要对象,并使用jsonb_agg()
将其聚合到json数组中:
select
key,
jsonb_agg(jsonb_build_object('category', category, 'avg_time', avg_time_1)) as avg_time_1,
jsonb_agg(jsonb_build_object('category', category, 'avg_time', avg_time_2)) as avg_time_2
from data_to_agg_json
group by key
key | avg_time_1 | avg_time_2
-----+----------------------------------------------------------------------+----------------------------------------------------------------------
1 | [{"avg_time": 10, "category": 10}, {"avg_time": 30, "category": 20}] | [{"avg_time": 20, "category": 10}, {"avg_time": 40, "category": 20}]
2 | [{"avg_time": 10, "category": 10}, {"avg_time": 60, "category": 20}] | [{"avg_time": 50, "category": 10}, {"avg_time": 70, "category": 20}]
(2 rows)