Question

@my_bot.event
async def on_message(message):
    if message.content.startswith('!test'):
        server = discord.Server
        await my_bot.send_message(server.get_member_named('mystery#5137'), 'Hello')

为什么不起作用？

错误：

Ignoring exception in on_message
Traceback (most recent call last):
  File "C:\Users\Roman-PC\AppData\Local\Programs\Python\Python36-32\lib\discord\client.py", line 307, in _run_event
    yield from getattr(self, event)(*args, **kwargs)
  File "C:/Users/Roman-PC/Desktop/t1.py", line 11, in on_message
    await my_bot.send_message(server.get_member_named('name'), 'Hello')
TypeError: get_member_named() missing 1 required positional argument: 'name'

Answer 1

您不应创建discord.Server，而应从message对象获得服务器（请参见docs中的discord.Message）

s = message.server

那么您可以

s.get_member_named('mystery#5137')

Answer 2

您需要使用名称定义成员。而不是：

server = discord.Server
await my_bot.send_message(server.get_member_named('mystery#5137'), 'Hello')

您需要：

server = message.server
await my_bot.send_message(server.get_member_named(name='mystery#5137'), 'Hello')

get_member_named（）缺少1个必需的位置参数：“名称”

2 个答案: