Question

我正在阅读本书的Python速成课程。我正在使用python3。在第16章中，有这样的代码：

import csv

filename = '/Users/pc/Desktop/CS 
Book/Python_crash_course_practice/16.1/sitka_weather_07-2014.csv'
with open(filename) as f:
    reader = csv.reader(f)
    header_row = next(reader)
    print(header_row)

但是它不起作用，并给我一个如下错误。我不知道该怎么解决。有没有人可以帮助我？谢谢。

%run -i "/Users/pc/Desktop/CS Book/Python_crash_course_practice/16.1/highs_lows.py"
---------------------------------------------------------------------------
UnicodeDecodeError                        Traceback (most recent call last)
/Users/pc/Desktop/CS Book/Python_crash_course_practice/16.1/highs_lows.py in <module>()
      4 with open(filename) as f:
      5     reader = csv.reader(f)
----> 6     header_row = next(reader)
      7     print(header_row)
      8 
/Users/pc/Library/Enthought/Canopy/edm/envs/User/lib/python3.5/encodings/ascii.py in decode(self, input, final)
     24 class IncrementalDecoder(codecs.IncrementalDecoder):
     25     def decode(self, input, final=False):
---> 26         return codecs.ascii_decode(input, self.errors)[0]
     27 
     28 class StreamWriter(Codec,codecs.StreamWriter):
UnicodeDecodeError: 'ascii' codec can't decode byte 0xc2 in position 1233: ordinal not in range(128)

Answer 1

文件中包含非ASCII字符，因此您需要在读取时指定文件编码。您还可以在python脚本的第一行中添加此代码，以将utf-8设置为默认编码

#!/usr/bin/env python # -*- coding: utf-8 -*-

python3'ascii'编解码器无法解码位置1233的字节0xc2：序数不在范围内（128）

1 个答案: