我在数据框中有多个数据。每个数据都有某种分布。
0 4 6
-0.276 4403 4403
-0.138 4640 4640
0 0 0
0.138 12 0
0.276 0 0
0.414 0 0
0.552 0 0
0.69 0 0
0.828 0 12
0.966 0 0
1.104 0 12
1.242 0 0
1.38 0 0
1.518 0 0
1.656 0 0
1.794 0 0
1.932 0 0
2.07 0 0
2.208 0 0
2.346 0 0
2.484 0 0
2.622 0 12
2.76 0 0
2.898 0 0
3.036 0 0
3.174 0 0
3.312 0 0
3.45 0 0
3.588 0 0
3.726 0 0
3.864 12 0
4.002 0 0
4.14 0 0
4.278 12 0
4.416 0 0
4.554 0 12
4.692 0 0
4.83 0 0
4.968 0 0
5.106 0 0
5.244 0 0
5.382 12 0
5.52 0 0
5.658 0 0
5.796 127 60
5.934 357 275
6.072 1882 2144
6.21 6726 6609
6.348 9398 11180
6.486 12784 18389
6.624 15863 20111
6.762 6739 10202
6.9 1684 1921
7.038 249 376
7.176 47 103
7.314 0 26
7.452 17 0
7.59 0 0
7.728 0 0
7.866 0 0
8.004 0 0
8.142 0 0
8.28 0 0
8.418 0 0
8.556 0 0
8.694 0 0
8.832 0 0
8.97 0 0
9.108 0 0
9.246 0 0
9.384 0 0
9.522 0 0
9.66 0 0
9.798 0 0
9.936 0 0
10.074 0 0
10.212 0 0
10.35 0 12
10.488 0 0
10.626 0 0
10.764 0 0
10.902 0 0
11.04 0 0
11.178 0 0
11.316 0 0
11.454 0 0
11.592 0 0
11.73 0 0
11.868 0 0
12.006 0 0
12.144 0 0
12.282 0 0
12.42 0 0
12.558 0 0
12.696 12 0
12.834 0 0
12.972 0 0
13.11 0 0
13.248 0 0
13.386 12 0
13.524 0 0
13.662 0 12
13.8 0 0
13.938 0 0
14.076 0 0
14.214 0 0
14.352 0 0
14.49 0 0
14.628 12 0
14.766 0 0
14.904 12 0
15.042 0 0
15.18 0 0
15.318 0 0
15.456 0 0
15.594 0 0
15.732 0 0
15.87 0 0
16.008 0 0
16.146 0 0
16.284 0 0
16.422 0 0
16.56 12 0
16.698 0 0
16.836 0 0
16.974 0 0
17.112 0 0
17.25 0 0
17.388 0 0
17.526 0 0
17.664 0 12
17.802 0 0
17.94 0 0
18.078 0 0
18.216 0 0
18.354 0 0
18.492 0 0
18.63 12 0
18.768 0 0
18.906 0 0
19.044 0 0
19.182 0 0
19.32 0 0
19.458 0 0
19.596 0 0
19.734 0 0
19.872 0 0
20.01 0 0
20.148 0 12
20.286 12 0
20.424 0 12
20.562 0 0
20.7 0 0
20.838 0 0
20.976 0 0
21.114 0 0
21.252 0 0
21.39 0 12
21.528 0 0
21.666 0 0
21.804 12 0
21.942 0 0
22.08 0 0
22.218 0 0
22.356 0 0
22.494 0 0
22.632 0 0
22.77 0 0
22.908 0 0
23.046 0 0
23.184 0 0
23.322 0 0
23.46 12 0
23.598 0 12
23.736 0 0
23.874 0 0
24.012 0 0
24.15 0 0
24.288 0 0
24.426 0 0
24.564 0 0
24.702 0 0
24.84 0 0
24.978 0 0
25.116 0 0
25.254 0 0
25.392 0 0
25.53 0 0
25.668 0 0
25.806 12 0
25.944 12 0
26.082 0 0
26.22 0 0
26.358 0 12
26.496 0 0
26.634 0 0
26.772 0 0
26.91 0 0
27.048 13 0
27.186 0 0
27.324 0 0
27.462 0 0
'0'列是我的x值。列“ 4”和“ 6”是数据“ 4”和“ 6”的y值。
如果我将列“ 4”与列“ 0”相对应，则会得到单峰分布。但是我想调整y值，使曲线下的面积为1。
我有两种策略。 （一个：梯形方法，第二个：将所有y值除以y的和）。
哪个是正确的？或者我该如何检查哪一个是正确的？
df = pd.read_csv('my_data.csv',header=0).iloc[2:,:]
x = df.iloc[:,0].values
df.iloc[:,1:] = df.iloc[:,1:]/df.iloc[:,1:].apply(lambda y: np.trapz(y,x=x), axis=0) #trapizoidal method
df.iloc[:,1:] = df.iloc[:,1:]/np.sum(df.iloc[:,1:]) #dividing by the sum