Question

如何将处理程序与progressBar链接？

fun start() {
    started = true
    handler.postDelayed(runnable, 13000)
}


private val runnable = Runnable {
    start()
}

Answer 1

还有其他解决方案，但我更喜欢：

final static int TH_MESSAGE_START = 0;
final static int TH_MESSAGE_PROGRESSION = 1;
final static int TH_MESSAGE_END = 2;

final ProgressBar mProgressBar = .....

final static Handler mHandler = new Handler(Looper.getMainLooper()) {
   @Override
   public void handleMessage(@NonNull final Message) {
      switch (message.what) {
         case TH_MESSAGE_START:
            mProgressBar.setProgress(0);
            break;
         case TH_MESSAGE_PROGRESSION:
            mProgressBar.setProgress(message.arg1);
            break;
         case TH_MESSAGE_END:
            mProgressBar.setProgress(mProgressBar.getMax());
            break;
      }
   }
};

private static boolean postToMainThread(final int what, final int arg1) {
   if (mHandler == null) return false;
   final Message cMessage = new Message();
   cMessage.what = what;
   cMessage.arg1 = arg1;
   return mHandler.sendMessage(cMessage);
}
private static boolean postToMainThread_progressBarStart() {
   return postToMainThread(TH_MESSAGE_START, 0);
}
private static boolean postToMainThread_progressBarProgress(final int progression) {
   return postToMainThread(TH_MESSAGE_PROGRESSION, progression);
}
private static postToMainThread_progressBarEnd() {
   return postToMainThread(TH_MESSAGE_END, 0);
}

然后，您可以从任何线程中调用这些postToMainThread_xxxx（）方法来同步“ mProgressBar”。

（我知道其中两个TH_MESSAGE没有用，但是用户可能想在开始和结束时做不同的事情）

将progressBar与Handler同步

1 个答案: