如何查找列是否包含TRUE或FALSE值?
答案 0 :(得分:4)
例如,您可以像这样评估单元格A1
:
Sub Demo()
Select Case Sheets("Sheet1").Range("A1")
Case True
MsgBox "Cell A1 is TRUE"
Case False
MsgBox "Cell A1 is FALSE"
Case Else
MsgBox "Cell A1 is neither True nor False"
End Select
End Sub
这里是一个替代解决方案,因为目标可能更多地是 整个 列的“ T / F摘要”:
Sub Demo2()
Dim cntT As Long, cntF As Long, resp As String
cntT = WorksheetFunction.CountIf(Sheets("Sheet1").Columns("A"), True)
cntF = WorksheetFunction.CountIf(Sheets("Sheet1").Columns("A"), False)
Select Case cntT
Case Is > 0
Select Case cntF
Case Is > 0
resp = "a mix of " & cntT & " TRUE and " & cntF & " FALSE."
Case Else
resp = cntT & " TRUE but no FALSE."
End Select
Case Else
Select Case cntF
Case Is > 0
resp = cntF & " FALSE but no TRUE."
Case Else
resp = "neither TRUE nor FALSE."
End Select
End Select
MsgBox "The column contains " & resp, vbInformation
End Sub
答案 1 :(得分:1)
=IFERROR(LOOKUP(TRUE,A:A),IFERROR(NOT(LOOKUP(FALSE,A:A)),"NEITHER FOUND"))
或
=IFERROR(IF(LOOKUP(TRUE,A:A),TRUE,IF(NOT(LOOKUP(FALSE,A:A)),FALSE)),"NEITHER FOUND")
或
IF(SUMPRODUCT(--(A:A=TRUE))>0,"True found",IF(SUMPRODUCT(--(A:A=FALSE))>0,"FALSE FOUND",))
或
Option Explicit
Public Sub Demo()
Dim arr(), i As Long
Const COL_NUMBER As Long = 1 '< =Col A
arr = Array(True, False)
For i = LBound(arr) To UBound(arr)
If Not ActiveSheet.Columns(COL_NUMBER).Find(arr(i)) Is Nothing Then
MsgBox arr(i) & " found in column " & COL_NUMBER
Exit Sub
End If
Next i
MsgBox "Neither True not False Found"
End Sub
作为函数调用(以使您可以轻松地在将列作为范围参数传递的工作表中用作UDF)
Option Explicit
Public Sub Test()
Dim rng As Range
Const COL_NUMBER As Long = 1 '< =Col A
Set rng = ActiveSheet.Columns(COL_NUMBER)
MsgBox IsTrueOrFalseFound(rng)
End Sub
Public Function IsTrueOrFalseFound(ByVal rng As Range) As String
Dim arr(), i As Long
arr = Array(True, False)
For i = LBound(arr) To UBound(arr)
If Not rng.Find(arr(i)) Is Nothing Then
IsTrueOrFalseFound = arr(i) & " found in column " & rng.Column
Exit Function
End If
Next i
IsTrueOrFalseFound = "Neither True not False Found"
End Function
答案 2 :(得分:1)
基于OP列出的简洁要求,我认为发布的前两个答案过于复杂。 CountIF
方法似乎是最有效的方法。
忽略OP标题,答案甚至不需要VBA。它可以只是一个单元格公式:
测试是否找到True:
=IF(COUNTIF(B:B,TRUE)>0,"There's a TRUE in the Column!","No true's found!")
测试是否找到True或False:
=IF(COUNTIF(B:B,TRUE)+COUNTIF(B:B,FALSE)>0,"There's either a True or False FOUND!","Nothing found")
如果确实需要在VBA中引用此活动,则可以使用类似的方法。
Dim SrchRNG As Range
Set SrchRNG = Range("B:B")
If Application.WorksheetFunction.CountIf(SrchRNG, True) + Application.WorksheetFunction.CountIf(SrchRNG, False) > 0 Then
'Here's when a true or false has been found
Else
'Code if neither is found
End If
答案 3 :(得分:0)
这是一个简单的单行代码,如果找到匹配项,则返回true,如果找不到匹配项,则返回false:
Debug.Print Not IsError(Application.Match(True, Range("A:A"), 0))
上面的代码检查布尔值True
,但是如果要检查字符串“ True”,只需在第一个参数中插入“ True”。