Question

我有一个管道，用于过滤客户的日期。现在看起来像：

import { Pipe, PipeTransform } from '@angular/core';
@Pipe({
  name: 'filter'
})
export class FilterPipe implements PipeTransform {
  transform(clients: any[], searchText: string): any[] {
    if(!clients) return [];
    if(!searchText) return clients;

    searchText = searchText.toLowerCase();
    return clients.filter( it => {
      if (it.firstName.toLowerCase().includes(searchText)) {
        return it.firstName.toLowerCase().includes(searchText);
      }
      if (it.lastName.toLowerCase().includes(searchText)) {
        return it.lastName.toLowerCase().includes(searchText);
      }
      if (it.street.toLowerCase().includes(searchText)) {
        return it.street.toLowerCase().includes(searchText);
      }
      if (it.city.toLowerCase().includes(searchText)) {
        return it.city.toLowerCase().includes(searchText);
      }
      if (it.zipCode.toLowerCase().includes(searchText)) {
        return it.zipCode.toLowerCase().includes(searchText);
      }
      if (it.country.toLowerCase().includes(searchText)) {
        return it.country.toLowerCase().includes(searchText);
      }
      if (it.email.toLowerCase().includes(searchText)) {
        return it.email.toLowerCase().includes(searchText);
      }
      if (it.phone.toLowerCase().includes(searchText)) {
        return it.phone.toLowerCase().includes(searchText);
      }
    });
  }
}

但是我明白，条件可以写得更短。请告诉我，我该怎么办？..

Answer 1

下面是写条件的一种较短方法：

    public void onPostExecute(Map<String, String> result) {
    String[] fromwhere = { "NAME","PRICE","SIZE" ,"RANGE","SUPPLIER"};

            int[] viewswhere = {R.id.Name_txtView , R.id.price_txtView,R.id.size_txtView};

            ADAhere = new SimpleAdapter(getActivity(), result, R.layout.list_valence, fromwhere, viewswhere);

            list.setAdapter(ADAhere);
}

Answer 2

您可以使用这种方式

return clients.filter(function (item: any) {
    for (let property in item) {
      if (item[property] === null) {
        continue;
      }
      if (item[property].toString().toLowerCase().includes(searchText)) {
        return true;
      }
    }
    return false;
  });

过滤管中的条件更短

2 个答案: