如何在Play 2.6.x(Scala)的以下.conf中访问customers
的排序列表:
customers {
"cust1" {
env1 {
att1: "str1"
att2: "str2"
}
env2 {
att1: "str3"
att2: "str5"
}
env3 {
att1: "str2"
att2: "str6"
}
env4 {
att1: "str1"
att2: "str2"
}
}
"cust2" {
env1 {
att1: "faldfjalfj"
att2: "reqwrewrqrq"
}
env2 {
att1: "falalfj"
att2: "reqwrrq"
}
}
"cust3" {
env3 {
att1: "xvcbzxbv"
att2: "hello"
}
}
}
List("cust1", "cust2", "cust3")
,在此示例中。
答案 0 :(得分:1)
class SomeClass @Inject()(config: Configuration) {
Logger.debug("Customers from config: " + config.underlying.getConfig("customers"))
}
会给你的。
Customers from config: Config(SimpleConfigObject(
{"cust1":{
"env1":{"att1":"str1","att2":"str2"},
"env2":{"att1":"str3","att2":"str5"},
"env3":{"att1":"str2","att2":"str6"},
"env4":{"att1":"str1","att2":"str2"}},
"cust2":{
"env1":{"att1":"faldfjalfj","att2":"reqwrewrqrq"},
"env2":{"att1":"falalfj","att2":"reqwrrq"}},
"cust3":{
"env3":{"att1":"xvcbzxbv","att2":"hello"}}}))
如果要使用对象,显然必须进行转换。
答案 1 :(得分:1)
以下示例应该起作用:
val config : Configuration = ???
config.getObject("customers").entrySet().asScala.map(_.getKey).toList
修改
如果客户按词典顺序排序,则可以致电.sorted
如果更改配置不会影响已经实施的逻辑,则可以像下面这样重新构造配置:
customers : [
{
name : "cust1"
env1 {
att1: "str1"
att2: "str2"
}
env2 {
att1: "str3"
att2: "str5"
}
env3 {
att1: "str2"
att2: "str6"
}
env4 {
att1: "str1"
att2: "str2"
}
}
{
name : "cust2"
env1 {
att1: "faldfjalfj"
att2: "reqwrewrqrq"
}
env2 {
att1: "falalfj"
att2: "reqwrrq"
}
}
{
name: "cust3"
env3 {
att1: "xvcbzxbv"
att2: "hello"
}
}
{
name : "bob"
env1 {
att1: "str1"
att2: "str2"
}
env2 {
att1: "str3"
att2: "str5"
}
env3 {
att1: "str2"
att2: "str6"
}
env4 {
att1: "str1"
att2: "str2"
}
}
{
name : "john"
env1 {
att1: "faldfjalfj"
att2: "reqwrewrqrq"
}
env2 {
att1: "falalfj"
att2: "reqwrrq"
}
}
{
name: "jack"
env3 {
att1: "xvcbzxbv"
att2: "hello"
}
}
]
,使用pureconfig,您可以执行以下操作:
import pureconfig.loadConfigOrThrow
final case class Named(name: String)
loadConfigOrThrow[List[Named]]("customers").map(_.name)