我想编写一个函数,该函数将记录每个组的输入,然后显示其输入。例如,
组输入:
predictions = pd.DataFrame(predictions[1])
actual = pd.DataFrame(y_test)
test = pd.concat([actual.reset_index(drop=True), predictions], axis=1)
# Rename column Renew to 'actual' and '1' to 'predictions'
test.rename(columns={"Renew": "actual", 1: "predictions"}, inplace=True)
TP = np.repeat('NA', 101)
FN = np.repeat('NA', 101)
FP = np.repeat('NA', 101)
TN = np.repeat('NA', 101)
Sensitivity = np.repeat('NA', 101)
Specificity = np.repeat('NA', 101)
AUROC = 0
for i in range(100):
test['temp'] = 0
test[test['predictions'] > (i/100), "temp"] = 1
TP[i+1] = [test[test["actual"]==1 and test["temp"]==1,]].shape[0]
FN[i+1] = [test[test["actual"]==1 and test["temp"]==0,]].shape[0]
FP[i+1] = [test[test["actual"]==0 and test["temp"]==1,]].shape[0]
TN[i+1] = [test[test["actual"]==0 and test["temp"]==0,]].shape[0]
Sensitivity[i+1] = TP[i+1] / (TP[i+1] + FN[i+1])
Specificity[i+1] = TN[i+1] / (TN[i+1] + FP[i+1])
if(i > 0):
AUROC = AUROC+0.5*(Specificity[i+1] - Specificity[i])*
(Sensitivity[i+1] + Sensitivity[i])
多少个小组:
groupOneInput = a, b, c
groupTwoInput = i, j, k
当前解决方案:
numOfGroups = 2
输出:
import scala.io.StdIn._
def x(numOfGroups: Int): String = {
(
if(numOfGroups <1) "Done"
else {
println("\nPlease enter your values:\n")
val input = readLine
input + x(numOfGroups-1)
}
)
}
所需的输出:
groupOne = a,b,c
groupTwo = i,j,k
谢谢
答案 0 :(得分:0)
<?php
require_once SMARTY_DIR . 'Smarty.class.php';
class Application extends Smarty
{
public function __construct()
{
parent::Smarty();
$this->template_dir = TEMPLATE_DIR;
$this->compile_dir = COMPILE_DIR;
$this->config_dir = CONFIG_DIR;
}
}
?>
在Scala REPL中:
def x(numOfGroups: Int): Unit = {
def y(numOfGroups:Int):String =
if(numOfGroups <1) "Done"
else { println("\nPlease enter your values:\n")
val input = readLine
input + y(numOfGroups-1)
}
val t = y(numOfGroups).dropRight(4).mkString.replaceAll(",","").
replaceAll(" ","").grouped(3).toList.map(x=>x.mkString(","))
val x = List("groupOne","groupTwo").zipWithIndex
for((i,j)<-x) println(i+" = "+t(j))
}