Question

我在这里有点问题。我已经检查了很多次错误了，但是所有的我都无法正常工作。因此，我必须创建一个读取3行输入的程序。这是关于一家杂货店，在一周和周末有两种不同的价格值。我必须使其仅输出水果的价格*数量，如果不存在日期或水果，则输出“错误”。我真的很困惑为什么我的代码无法正常工作。我才刚开始使用PHP，所以也许我只是没有太多经验。

$type = strtolower(readline());
$day = strtolower(readline());
$quantity = floatval(readline());
$days = array("monday", "tuesday", "wednesday", "thursday", "friday");
$weekend = array("saturday", "sunday");
$fruit_normal = array(
    "2.50" => "banana",
    "1.20" => "apple",
    "0.85" => "orange",
    "1.45" => "grapefruit",
    "2.70" => "kiwi",
    "5.50" => "pineapple",
    "3.85" => "grapes"
);
$fruit_we = array(
    "2.70" => "banana",
    "1.25" => "apple",
    "0.90" => "orange",
    "1.60" => "grapefruit",
    "3.00" => "kiwi",
    "5.60" => "pineapple",
    "4.20" => "grapes"
);
$search = array_search($day, $days);
$search1 = array_search($day, $weekend);
$search2 = array_search($type, $fruit_normal);
$search3 = array_search($type, $fruit_we);
if ($search != NULL && $search2 != NULL) {
    $price = $search2 * $quantity;
    $formatted = number_format($price, 2);
    print $formatted;
} elseif ($search1 != NULL && $search3 != NULL) {
    $price = $search3 * $quantity;
    $formatted = number_format($price, 2);
    print $formatted;
} elseif ($search == NULL && $search1 == NULL && $search2 == NULL && $search3 == NULL) {
    echo "error";
}

Answer 1

所以这就是我解决问题的方式，首先我制作了所有仅由参数组成的数组，从1开始。然后在检查{{的结果时，将所有NULL的值替换为FALSE 1}}我仍然不确定真正的问题是什么，但是现在我会接受的。

array_search

也许是一个简单的数组问题

1 个答案: