我希望有人能给我一些可以返回执行以下操作的日历数据的示例。
示例:
input('Year:')- 2018
input('Month:')- 7
最终结果:(2018年)(七月)的工作日数为( 22 )。
示例:
input('Year:')- 2018
input('Month:')- 7
input('date:')- 20
最终结果:(20)是(星期五),是( 15 )< (七月),(2018年)的strong>工作日。
这是到目前为止我已经能够创建的代码...
import calendar
year = float(input('Year: '))
month = float(input('Month: '))
input_year = []
input_month = []
if year >= 1000 and year <=3000:
input_year.append(year)
if month >= 1 and month <=12:
input_month.append(month)
cal_format = calendar.TextCalendar(calendar.MONDAY)
result_cal = cal_format.formatmonth(int(input_year[0]), int(input_month[0]))
print(result_cal)
THE END RESULT IS...
Year: 1978
Month: 3
March 1978
Mo Tu We Th Fr Sa Su
1 2 3 4 5
6 7 8 9 10 11 12
13 14 15 16 17 18 19
20 21 22 23 24 25 26
27 28 29 30 31
这仅打印出带有星期六的文本日历。和Sun在每个周末结束,因此我至少可以在视觉上排除它们。但我真的很希望能够以编程方式排除它们,并能够输入上述变量来计算一个月中的工作日,以及该月中每天的哪个工作日。
答案 0 :(得分:1)
要获取一个月中的工作日数:
import calendar
weekdays = 0
cal = calendar.Calendar()
for week in cal.monthdayscalendar(2018, 7):
for i, day in enumerate(week):
# Check if is a weekday and the day is from this month
if i < 5 and day != 0:
weekdays += 1
print weekdays
要获取特定日期的星期几,您可以修改上面的代码以在达到输入日期时返回星期几。
答案 1 :(得分:1)
这是查找以前工作日数量的一种方法:
请注意,年,月,日的类型转换为int
。
import calendar
year = int(input('Year: '))
month = int(input('Month: '))
day = int(input('Day: '))
full_wks = day / 7
extra_days = day % 7
first_day = calendar.weekday(year, month, 1)
if first_day >= 5: # if month begins on a weekend
weekend = 7 - first_day # yields 1 if Sunday, 2 if Saturday
extra_days -= weekend
weekdays = full_wks * 5 + extra_days
ordinal = lambda n: "{}{}".format(n, 'tsnrhtdd'[n%5*(n%100^15>4>n%10)::4])
print "{}/{} is the {} weekday in the month.".format(month, day, ordinal(weekdays))
输出:
Year: 2018
Month: 7
Day: 20
7/20 is the 15th weekday in the month.
从Code Golf上的xsot转换序数。
答案 2 :(得分:0)
检查日期的工作日的一种方法是使用date
对象的weekday()
方法。它在python标准库datetime
模块中。
date.weekday()
以整数形式返回星期几,其中星期一为0,星期日为6。例如,
date(2002, 12, 4).weekday() == 2
,星期三。另请参见isoweekday()
。
import datetime
num_of_weekdays = 0
weekday_list = []
start_date = datetime.date(int(input_year[0]), int(input_month[0]), 1)
cur_date = start_date
while cur_date.month == start_date.month:
if 0 <= cur_date.weekday() <= 4: # if it is a weekday
num_of_weekdays += 1
weekday_list.append(cur_date.day)
cur_date += datetime.timedelta(days=1)
print("The number of weekdays in ({}) of ({}) is ({}).".format(
input_month[0], input_year[0], num_of_weekdays))
date_ = datetime.date(int(input_year[0]), int(input_month[0]), int(input_date[0]))
index = weekday_list.index(int(input_date[0])) + 1
print("The ({}) is a ({}) and is the ({}) weekday of ({}), ({}).".format(
date_.day, date_.strftime('%A'), index, date_.month, date_.year)
答案 3 :(得分:0)
我在大约10分钟内提出了一个简单的解决方案。我的方法在很大程度上依赖于列表推导和字符串方法,例如join和split,因此,如果您还不熟悉它们,我建议您查找它们。首先将结果分成几行,需要重新定义标题,其他行需要删除最后一个字符。
使用strip()方法将第一行居中对齐,以删除该行开头的空白,然后预先添加两个空格。
利用列表推导,每周末仅包含前15个字符。
最后一部分是最难的。这个想法是要计算我格式化的日历中有多少天数。首先将所有带日期数字的行放到一个大行中,然后用空格将其分隔以获取所有日期数字的列表,最后使用列表的大小。
import calendar
year = float(input('Year: '))
month = float(input('Month: '))
input_year = []
input_month = []
if year >= 1000 and year <=3000:
input_year.append(year)
if month >= 1 and month <=12:
input_month.append(month)
cal_format = calendar.TextCalendar(calendar.MONDAY)
result_cal = cal_format.formatmonth(int(input_year[0]), int(input_month[0]))
lines = result_cal.split("\n") # Split result_cal into a list of lines
title_line = lines[0] # Save first line, we want to edit this differently
title_line = " " + title_line.strip() # Change the indentation of the title line
lines = lines[1:] # Now select lines below the first
lines = [line[:3*5] for line in lines] # Only Keep first 15 characters or each
# line to exclude weekends. (5 weekdays *
# 3 chars per day)
lines = [line for line in lines if len(line.strip())] # Don't include empty lines
# happens if month starts
# on a weekend.
# prints out the result
print(title_line)
for line in lines:
print(line)
# Next work out how many working days in month.
nums = "".join(lines[1:]).split(" ") # Three parts: first lines[1:] means this
# only looks at the portion of the calendar
# with numbers written on then. 2nd "".join()
# joins the lines into a single string on 1 line
# 3rd the .split(" ") splits the string based on spaces
# unfortunatly 2 consecutive spaces result in an empty
# string.
nums = [num for num in nums if len(num)] # Filters the empty string.
print(f"There are {len(nums)} working days in the month you selected") # Prints result
#(uses f-string, you may want to look them up, I find them to be very useful)