Question

这是一个Spring MVC项目，其中的视图通过servlet-dispatcher.xml重定向。调度程序无法映射到给定的URI。附加的图像包含项目结构，这也可能有助于发现错误。以下是代码：-

Web.xml

<?xml version="1.0" encoding="UTF-8"?>

<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">


<display-name>Test Web Application</display-name>

<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>
        org.springframework.web.servlet.DispatcherServlet
    </servlet-class>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/dispatcher-servlet.xml</param-value>
</context-param>

<listener>
    <listener-class>
        org.springframework.web.context.ContextLoaderListener
    </listener-class>
</listener>

调度程序

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">

<context:component-scan base-package="com.practice.controller" />
<context:annotation-config/>
<bean
    class="org.springframework.web.servlet.view.InternalResourceViewResolver">
    <property name="prefix">
        <value>/WEB-INF/views/</value>
    </property>
    <property name="suffix">
        <value>.jsp</value>
    </property>
</bean>

控制器

package com.practice.controller;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestParam;
import org.springframework.web.servlet.ModelAndView;

@Controller
public class Test {
String msg = "Hello Nigga";

@RequestMapping("/test")
public ModelAndView testController(
        @RequestParam(value="name", required=false, defaultValue="Yooo") 
            String name){
    System.out.println("Test Controller");

    ModelAndView mv = new ModelAndView("testView");
    mv.addObject("msg",msg);
    mv.addObject("name", name);
    return mv;
}

}

Console: Error

Project Structure

谢谢。

Answer 1

我认为它不起作用，因为您仅实现了根上下文（通过contextConfigLocation参数启用）。您应该为spring servlet添加上下文。您可以在第20-23行中看到示例here。 Servlet的上下文描述为here

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/spring/root-context.xml</param-value>
</context-param>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/spring/appServlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

春季：在Dispatcher Servlet

1 个答案: