我想知道如何从FormView类处理GET
或POST
请求,以为GET
呈现未绑定的表单,并为{{1 }},然后重定向到成功页面(信息消息)。
用于POST
和GET
方法的模板以及重定向到成功URL后如何包含消息?
views.py:
POST
urls.py:
from django.shortcuts import render,redirect,render_to_response,get_object_or_404
from django.forms import ModelForm
from django.views import View
from django.views.generic.edit import CreateView
from .forms import MyPlaceForm
from .models import Place
from django.urls.base import reverse_lazy
from django.contrib import messages
#Ceate your class-based views here.
class MapView(View):
def get(self, request):
'Display map'
return render(request,template_name='index.html')
# Handling forms with class-based view
class PlaceFormView(View):
form_class = MyPlaceForm
initial = {'key': 'value'}
template_name = 'name.html'
# Provide Blank Form if GET request
def get(self, request, *args, **kwargs):
form = self.form_class(initial=self.initial)
return render(request, self.template_name, {'form': form})
# Provide a message if POST request
def post(self, request, *args, **kwargs):
form = self.form_class(request.POST)
success_url=reverse_lazy('success')
if form.is_valid():
# <process form cleaned data>
messages.add_message(request, messages.INFO, 'Hello world.')
return reverse_lazy(success_url)
return render(request, self.template_name, {'form': form})
答案 0 :(得分:0)
在documentation之后,您可以执行以下操作:
# views.py
if request.method == "POST":
if form.is_valid():
# <process form cleaned data>
messages.success(request, 'Form updated with success.')
return redirect('/success-page')
else:
messages.error(request, 'Ops! Something went wrong')
return redirect('/error-page')
在模板页面中,您可以使用for循环代码获取消息:
{% if messages %}
{% for message in messages %}
<div {% if message.tags %} class="alert alert-{{ message.tags }} alert-dismissible fade show" {% endif %}>
<span>{{ message }}</span>
</div>
{% endfor %}
{% endif %}
Edit1 :确保已导入message标签并在视图中重定向。py
from django.contrib import messages
from django.shortcuts import render, redirect