我正在尝试使用Comparator.comparing()
对具有其成员属性的列表进行排序,并且该属性是由用户选择的。考虑以下情况:
public class MyClass extends BaseClass
{
private String attr1;
private Date attr2;
private ChildClass attr3;
//getter and setter
}
public class ChildClass extends BaseClass
{
private String attr1;
private Date attr2;
private int attr3;
//getter and setter
}
这是我尝试过的,但是有编译错误。
private Map<String, Function<MyClass, ?>> sortingOptions = new HashMap<>();
private String sortBy; //sorting attribute selected by user
@PostConstruct
public void init()
{
//my list to be sort
List<MyClass> list = myService.getList();
sortingOptions.put("attr1", MyClass::getAttr1);
sortingOptions.put("attr2", MyClass::getAttr2);
//......
}
//listener for sorting option changed
public void sortOptionChangedListener()
{
//this line of code having error
list.sort(Comparator.comparing(sortingOptions.get[sortBy]));
}
显示的错误是
The method comparing(Function<? super T,? extends U>) in the type Comparator is not applicable for the arguments (Function<MyClass,capture#3-of ?>)
答案 0 :(得分:5)
仅将方法引用存储在Map中而不是现在使用的Function中可能会更容易。考虑一下...
public class BaseClass implements Comparable<BaseClass> {
@Override
public int compareTo(BaseClass o) {
// implement this properly
return 0;
}
}
public class MyClass extends BaseClass {
private String attr1;
private Date attr2;
private ChildClass attr3;
//getter and setter
}
public class ChildClass extends BaseClass
{
private String attr1;
private Date attr2;
private int attr3;
//getter and setter
}
private List<MyClass> list;
private Map<String, Comparator<? super MyClass>> sortingOptions = new HashMap<>();
private String sortBy; //sorting attribute selected by user
@PostConstruct
public void init()
{
//my list to be sort
list = myService.getList();
sortingOptions.put("attr1", Comparator.comparing(MyClass::getAttr1));
sortingOptions.put("attr2", Comparator.comparing(MyClass::getAttr2));
sortingOptions.put("attr3", Comparator.comparing(MyClass::getAttr3));
//......
}
public void sortOptionChangedListener()
{
list.sort(sortingOptions.get(sortBy));
}
答案 1 :(得分:0)
我认为克林顿是正确的。以下是Comparator ::比较源代码。
ICar
其参数是一个函数,其输入参数为T并且返回值为Comparable,这不适用于简单的getter。我认为反射可以做到这一点,但更为复杂。
答案 2 :(得分:-1)
您可以这样做:
private Map<String, Function<MyClass, ? extends Comparable>> sortingOptions = new HashMap<>();
您可能必须忍受警告,一个警告sortingOptions
,另一个警告list.sort()
。
如果您希望它变得更整洁,可以制作一个辅助方法。
@SuppressWarnings("unchecked")
private <T, U extends Comparable<U>> Function<? super T, ? extends U> getComparator(String sortBy) {
return (Function<T, U>) sortingOptions.get(sortBy);
}
用法:
list.sort(Comparator.comparing(getComparator(sortBy)));
您应该按照克林顿的建议进行操作,这种方法更加简洁。