Question

我有这个用例。

Project:
  has_many :assignments

Assignment:
  has_many :assignments_users, class_name: "AssignmentsUsers"
  has_many :assignees, through: :assignments_users, source: :user

assignments_users：只是user_id和Assignment_id。

我希望能够做这样的事情。

projects = Project.includes(:assignments, {assignments: :assginments_users}).where("assignments.assignments_users.user_id = 6")

如果要访问列表中给定项目的分配，则只会看到分配的用户之一是ID为6的用户的分配。

这甚至可以吗？

我在想，也许我会多赚has_many my_assignments, (user_id) -> { where(match_something_to_my_user_id) }

那有可能吗？

Answer 1

您的示例非常接近应该起作用的地方：

projects = Project.
  includes(assignments: :assignments_users).
  where(assignments_users: { user_id: 6 })

或者，从另一侧接近可能会更整洁：

Assignment:
  belongs_to :project

User:
  has_many :assignments_users, class_name: "AssignmentsUsers"
  has_many :assignments, through: :assignments_users
  has_many :active_projects, through: :assignments, source: :project

my_user.active_projects

Rails活动记录包括条件

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