Question

models.py

from django.db import models
from django.urls import reverse


# Create your models here.
class WellInfo(models.Model):
    api = models.CharField(max_length=100, primary_key=True)
    well_name = models.CharField(max_length=100)
    status = models.CharField(max_length=100)
    phase = models.CharField(max_length=100)
    region = models.CharField(max_length=100)
    start_date = models.CharField(max_length=100)
    last_updates = models.CharField(max_length=100)

    def __str__(self):
        return self.well_name

views.py

class ContextualMainView(TemplateView):
    template_name = 'contextual_main.html'


class WellList_ListView(ListView):
    template_name = 'well_list.html'
    context_object_name = 'well_info'
    model = models.WellInfo

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)

        # get string representation of field names in list
        context['fields'] = [field.name for field in models.WellInfo._meta.get_fields()]

        # nested list that has all objects' all attribute values
        context['well_info'] = [[getattr(instance, field) for field in context['fields']] for instance in context['well_info']]

        return context

html

<thead>
  <tr>
    {% for field in fields %}
    <th>{{ field }}</th>
    {% endfor %}
  </tr>
</thead>
<tbody>
  {% for well in well_info %}
  <tr>
    {% for value in well %}
    <td><a href="{% url 'eric_base:contextual' api=well.api %}">{{ value }}</a></td>
    {% endfor %}
  </tr>
  {% endfor %}
</tbody>

app / urls.py

from django.urls import re_path, include
from django.contrib.auth import views as auth_views
from eric_base import views as base_views

app_name = 'eric_base'

urlpatterns = [

        re_path(r'^(?P<api>\d+)/$', base_views.ContextualMainView.as_view(), name='contextual'),

]

在我的models.py中，我将api设置为主键，并希望使用api作为唯一的URL标识符，并将其附加在url的末尾，如下所示：

http://127.0.0.1:8000/well_list/contextual/api_number_1
http://127.0.0.1:8000/well_list/contextual/api_number_2
http://127.0.0.1:8000/well_list/contextual/api_number_3

我认为我的views.py或models.py中缺少某些内容，但我不知道它是什么。我该如何解决？

Answer 1

您的正则表达式function drawPath(source, desti, flag) { /* * Define context */ //lower if(!flag){ var c = document.getElementById("myCanvas"); context = c.getContext("2d"); //upper } else { var cUpr = document.getElementById("myCanvasUpr"); context = cUpr.getContext("2d"); } /* * Clear the variables */ points = []; secondary_points = []; vertices = []; secondary_vertices = []; t = 1; done = false; //check for invalid locations if (source != "" && desti != "") { context.lineCap = 'round'; context.beginPath(); /* * Get the coordinates from source and destination strings */ var src = dict[source]; var dst = dict[desti]; /* * Get the point number of the point on the path that the source and destination connect to */ var begin = point_num[source]; var finish = point_num[desti]; /* * Draw the green and red starting/ending circles (green is start, red is end) */ context.beginPath(); context.arc(src[0], src[1], 8, 0, 2 * Math.PI); context.fillStyle = 'green'; context.fill(); context.beginPath(); context.arc(dst[0], dst[1], 6, 0, 2 * Math.PI); context.fillStyle = 'red'; context.fill(); /* * Call the function that draws the entire path */ draw_segments(begin, finish, src, dst, flag); //window.alert(JSON.stringify(vertices, null, 4)) /* * Edit what the line looks like */ context.lineWidth = 5; context.strokeStyle = "#ff0000"; context.stroke(); } }是一个数字，但是(?P<api>\d+)字段是一个api。

尝试CharField，它将匹配所有内容，而不仅仅是数字。

Django-找不到带有关键字参数'{'api'：''}'的'contextual'

1 个答案: