我正在尝试将excel电子表格上传到SharePoint Online网站上的文档库。 excel电子表格中列出了SharePoint网站上的Sharepoint URL和文件夹位置。
这是我现在拥有的代码:
import numpy as np
import pandas as pd
import xlwings as xw
from xlwings.constants import Direction
import sys
import requests
from requests_ntlm import HttpNtlmAuth
pd.options.mode.chained_assignment = None
def Upload():
wb = xw.Book.caller()
ws = wb.sheets['Sheet1']
#Read filename from excel
fileName = sys.argv[1]
#Enter SharePoint ONline site and target library
SP_URL = ws.range('C7').value
folder_URL = ws.range('C8').value
#Set up the url for requesting file upload
request_URL = SP_URL + '/_api/web/getfolderbyserverrelativeurl(\'' +
folder_URL + '\')/Files/asdd(url=\'' + fileName + '\',overwrite=true)'
#read in the file that we are going to upload
file = open(fileName, 'rb')
headers = {'Content-Type': 'application/json; odata=verbose', 'accept':
'application/json;odata=verbose'}
r = requests.post(SP_URL +
"/_api/contextinfo",auth=HttpNtlmAuth('Domain\\username','password'),
headers=headers)
formDigestValue = r.json()['d']['GetContextWebInformation']
['FormDigestValue']
headers = {'Content-Type': 'application/json; odata=verbose', 'accept':
'application/json;odata=verbose', 'x-requestdigest' : formDigestValue}
uploadResult =
requests.post(request_URL,auth=HttpNtlmAuth('Domain\\username','password'),
headers=headers, data=file.read())
我收到以下错误:
formDigestValue = r.json()['d'] ['GetContextWebInformation'] ['FormDigestValue']
KeyError:'d'
答案 0 :(得分:1)
允许使用请求库进行HTTP NTLM身份验证
但是 SharePoint Online 不支持 NTLM 。
例如,我建议使用requests_ntlm(而不是Office365-REST-Python-Client
(它支持指定用户凭据并使用SharePoint REST API )包将文件上传到SharePoint Online。 :
ctx_auth = AuthenticationContext(url=settings['url'])
if ctx_auth.acquire_token_for_user(username=settings['user_credentials']['username'],
password=settings['user_credentials']['password']):
ctx = ClientContext(settings['url'], ctx_auth)
target_list = ctx.web.lists.get_by_title("Documents")
info = FileCreationInformation()
file_name = "Book.xlsx"
path = "{0}/data/{1}".format(os.path.dirname(__file__), file_name)
with open(path, 'rb') as content_file:
info.content = content = content_file.read()
info.url = file_name
info.overwrite = True
upload_file = target_list.root_folder.files.add(info)
ctx.execute_query()