Question

如何在JavaScript中的filter中应用filter，同时在数组中查找数组中的值？

说，我想获得团队中包括construction的所有Jane Smith项目。

我意识到我在这里发明了一些疯狂的JavaScript，我只是想向您展示我的追求。

const result = myArray.filter(x => x.type === "construction" && x.team.filter(y => y.name.includes("Jane Smith")));

这是我要过滤的数组：

[
   {
      "type": "construction",
      "name": "Project A",
      "team": [
         {
            "name": "John Doe",
            "position": "Engineer"
         },
         {
            "name": "Jane Smith",
            "position": "Architect"
         }
      ]
   },
   {
      "type": "construction",
      "name": "Project B",
      "team": [
         {
            "name": "Walt Disney",
            "position": "Creative Director"
         },
         {
            "name": "Albert Einstein",
            "position": "Scientist"
         }
      ]
   },
   {
      "type": "remodelling",
      "name": "Project C",
      "team": [
         {
            "name": "John Travolta",
            "position": "Manager"
         }
      ]
   }
]

Answer 1

您可以使用Array#some来检查团队。

此提案使用destructuring assignment作为对象。

var array = [{ type: "construction", name: "Project A", team: [{ name: "John Doe", position: "Engineer" }, { name: "Jane Smith", position: "Architect" }] }, { type: "construction", name: "Project B", team: [{ name: "Walt Disney", position: "Creative Director" }, { name: "Albert Einstein", position: "Scientist" }] }, { type: "remodelling", name: "Project C", team: [{ name: "John Travolta", position: "Manager" }] }],
    result = array.filter(({ type, team }) =>
        type === "construction" && team.some(({ name }) => name === "Jane Smith"));

console.log(result);

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Answer 2

也许类似以下内容？

const result = myArray.filter(x => x.type === "construction" && x.team.filter(y => y.name.includes("Jane Smith")).length > 0);

基本上，我只是检查新过滤后的数组长度是否大于0。

在JavaScript的过滤器中应用过滤器

2 个答案: