Question

我想从mySubView中点击返回按钮。我有带按钮的付款ViewController，此按钮使view.addSubview（WkWebView）。因此，我可以打开WkWebView，但我无法丢失它。

我的代码：

self.automaticallyAdjustsScrollViewInsets = false
self.wkWebView.translatesAutoresizingMaskIntoConstraints = false
self.wkWebView.frame =  CGRect.init(x: 0, y: 0, width: self.wkWebView.frame.size.width, height: self.wkWebView.frame.size.height)
self.view.addSubview(wkWebView)

loadUrl()

func loadUrl(){
    let webConfiguration = WKWebViewConfiguration()
    webConfiguration.allowsInlineMediaPlayback = true

    let myURL = URL(string: "https://ecg.test.upc.ua/go/enter")
    var myRequest = URLRequest(url: myURL!)
    myRequest.httpMethod = "POST"
    wkWebView.load(myRequest)
}

Answer 1

您可以尝试

let back = UIButton(type: .system)

back.frame = CGRect(x: 10, y: 20, width: 100, height: 50)

back.setTitle("Back", for: .normal)

back.sizeToFit()

back.addTarget(self, action: #selector(self.back), for: .touchUpInside)

wkWebView.addSubview(back)

//

@objc func back() { 

    wkWebView.removeFromSuperview()

}

//

还为与SuperView相关的wkWebView提供了一个框架，并且不要在添加约束时设置self.wkWebView.translatesAutoresizingMaskIntoConstraints = false

self.wkWebView.frame = self.view.framw

Swift 4从子视图返回

1 个答案: