Question

我在项目存储库“论坛”中有这样的urls.py配置

# Project url
urlpatterns = [
    url(r'^admin/', admin.site.urls),
    url(r"^$", views.index, name="index"),
    url(r'^article/', include('article.urls',namespace='article')),
]

，其中article/urls.py为

#Article app's url config
urlpatterns = [
    # show the article list
    url(r"^list/(?P<block_id>\d+)$", views.article_list, name="article_list"),

我尝试将“ ^ article / list / 1 $”作为首页，而不是“ views.index”。

当我发出请求“ 127.0.0.1:8000”时，如何使其重定向到"^article/list/1$"？

Answer 1

您可以从您的views.index重定向。在您的views.py

from django.shortcuts import redirect

def index(request):
    return redirect('article:article_list')

应该带您进入文章/列表。您可以在重定向功能中包含该block_id参数。

Answer 2

尝试

redirect(reverse('article:article_list', kwargs={'block_id':2}))

并确保在这样的函数中添加kwargs

article_list(request,**kwargs):

Answer 3

我假设您要以此调试您的文章页面。您有两种方法可以做到这一点。

将索引视图重定向到文章视图

views.py

    from django.shortcuts import redirect
    def index(request):
        #We force a redirect to article_list view, and we pass arguments.
        #Notice it has to come first.
        redirect ("article_list", article_list_argument_view=1)
        #it will redirect to localhost:8000/article/list/1
        '''
        Your  Home page code.
        '''

将网址直接放在包含内容之前

urls.py

    urlpatterns = [

    url(r'^admin/', admin.site.urls),

    url(r"^$", views.index, name="index"),

    #The order is important.
    url(r'^article/list/1$', "article_list",     {'article_list_argument_view':1})

    url(r'^article/', include('article.urls',namespace='article')),
    ]

将任意网址设为首页

3 个答案: