Question

我遇到这个问题，我想用id标识客户端。我希望该ID仅是一个数字。有任何想法吗？预先感谢。

    int id = IBIO.inputInt("Enter the clients id:");

    boolean Clientexists = clientsAdm.existsClient(id) > 0;
    if (Clientexists != true) {

        String name = IBIO.inputString("Enter the client name:");
        String surname = IBIO.inputString("Enter the client surname:");
        String address = IBIO.inputString("Enter the client address:");
        String phone = IBIO.inputString("Enter the client phone:");
        String CreditCard = IBIO.inputString("Enter the type of card the client has: green, red or gold");  //asegurar que solo se ingrese RED, GREEN or GOLD
        Client c = new Client(name, surname, address, phone, CreditCard, id);

        clientsAdm.addClient(c);
    } else {

        IBIO.output("Error, this ID already exists.");

    }

    IBIO.output("Your client has been added.");
}

Answer 1

这可能有效，如果您给我更多详细信息，也许我可以帮您打个招呼

cleartool lsvtree {my file} | findstr CHECKEDOUT

否则，您可以尝试以下操作：

       int id = IBIO.inputInt("Enter the clients id:");

        boolean Clientexists = clientsAdm.existsClient(id) > 0;
        if (Clientexists != true) {
                String name = IBIO.inputString("Enter the client name:");
            String surname = IBIO.inputString("Enter the client surname:");
            String address = IBIO.inputString("Enter the client address:");
            String phone = IBIO.inputString("Enter the client phone:");
            String CreditCard = IBIO.inputString("Enter the type of card the client has: green, red or gold");  //asegurar que solo se ingrese RED, GREEN or GOLD
            Client c = new Client(name, surname, address, phone, CreditCard, id);


if(id instanceof Integer) {
clientsAdm.addClient(c);
} else {
IBIO.output("Id is not valid");
}
        } else {
                IBIO.output("Error, this ID already exists.");
            }
            IBIO.output("Your client has been added.");
    }

Answer 2

如果ID的非法输入为零，则可以检查ID是否为零，因为当IBIO.inputInt(String prompt)被赋予非整数时，prompt返回零。

如果ID的合法输入为零，则不能使用IBIO.inputInt(String prompt)。当将非整数传递给IBIO.inputInt时，将屏蔽该异常，并返回零。相反，您将需要定义自己的方法来读取用户输入。您可以执行以下操作：

static int inputIntWithRetry(String prompt) {
   int result = 0;
   int numberOfRetry = 5; // holds the number of times to reprompt the user
   boolean isInt = false; // flag for exiting the loop early if user provides a int
   for(int i = 0; i < numberOfRetry || !isInt; i++) {
      try {
         result = Integer.valueOf(
         input(prompt).trim()).intValue();
         isInt = true;
      } catch (Exception e) {
         System.out.println("Id is not valid");
      }
   }
   if (isInt) {
      return result;
   } else {
      // handle not receiving an int after 5 tries
   }
}

如何使一个Int只接受整数？

2 个答案: