请告诉我,这是我要完成的作业。我们要做的基本事情是创建一个没有STL的堆栈和队列,然后创建带有STL的堆栈和队列。我几乎完成了创建自定义堆栈的工作,并且效果很好。但是,使用Queue时,每当我尝试将字符串移入并打印出来时,控制台只会输出最后移出的字符串。最重要的是,每当我尝试取消使用我拥有的代码输入到队列中的最后一个东西时,最终都会遇到读取访问冲突,我完全无法解决读取访问冲突。
如果您不介意的话,您可以浏览我的代码并帮助我了解造成此错误的原因是什么,并且队列中的最后一个条目是唯一打印出来的吗?提前致谢。
#include "stdafx.h"
#include <iostream>
#include <string>
using namespace std;
struct Node {
//create a node struct
string data;
Node *next;
};
class Stack {
public:
Stack();
~Stack();
void push(string a);
string pop();
string toString();
bool isEmpty();
private:
Node * top;
};
class Queue {
public:
Queue();
~Queue();
void shift(string a);
string unshift();
string toString();
bool isEmpty();
private:
Node * top;
Node * bottom;
int count;
};
Stack::Stack() {
//initializes stack to be empty
top = NULL;
}
Queue::Queue() {
//initializes stack to be empty
top = NULL;
}
Stack::~Stack() {
//deconstructor to delete all of the dynamic variable
if (top == NULL) {
cout << "Nothing to clean up" << endl;
}
else {
cout << "Should be deleting..." << endl;
}
}
Queue::~Queue() {
//deconstructor to delete all of the dynamic variable
if (bottom == NULL) {
cout << "Nothing to clean up" << endl;
}
else {
cout << "Should be deleting..." << endl;
}
}
void Stack::push(string a) {
//Need a new node to store d in
Node *temp = new Node;
temp->data = a;
temp->next = top;//point the new node's next to the old top of the stack
top = temp;//point top to the new top of the stack
}
void Queue::shift(string a) {
//Need a new node to store d in
Node *temp = new Node;
temp->data = a;
temp->next = NULL;//point the new node's next to the old top of the stack
if (isEmpty()) {
top = temp;
}
else {
top->next = temp;
count++;
}
top = temp;//point top to the new top of the stack
}
string Stack::pop() {
if (!isEmpty()) {
string value = top->data;
Node *oldtop = top;
top = oldtop->next;
delete oldtop;
return value;
}
else {
cout << "You can't pop from an empty stack!" << endl;
exit(1);
}
}
string Queue::unshift() {
if (isEmpty()) {
cout << "You can't unshift an empty Queue!" << endl;
exit(1);
}
else{
Node *oldbot = top;
if (top == bottom) {
top = NULL;
bottom = NULL;
}
else {
string value = top->data;
}
delete oldbot;
count--;
}
}
string Stack::toString() {
string result = "top ->";
if (isEmpty()) {
result = result + "NULL";
return result;
}
else {
Node *current = top;
while (current != NULL) {
result = result + current->data + "->";
current = current->next;
}
result = result + "(END)";
return result;
}
}
string Queue::toString() {
string result = "top ->";
if (isEmpty()) {
result = result + "NULL";
return result;
}
else {
Node *current =top;
while (current != NULL) {
result = result + current->data + "->";
current = current->next;
}
result = result + "(END)";
return result;
}
}
bool Stack::isEmpty() {
return(top == NULL);
}
bool Queue::isEmpty() {
return(top == NULL);
}
int main()
{
Stack *s = new Stack();
cout << "Output when empty: " << endl << s->toString() << endl;
s->push("Cheeseburger");
s->push("Pizza");
s->push("Large coffee");
s->pop();
cout << "Output when not empty: " << endl << s->toString() << endl;
delete s;
cin.get();
Queue *b = new Queue();
cout << "Output when empty: " << endl << b->toString() << endl;
b->shift("Cheeseburger");
b->shift("Pizza");
b->shift("Large coffee");
cout << "Output when not empty: " << endl << b->toString() << endl;
b->unshift();
delete b;
cin.get();
}
答案 0 :(得分:0)
您必须在Queue :: shift方法中的以下语句中进行注释-
top = temp;