Question

我已经编写了这段代码，但是我应该准备好语句，我已经尝试过但没有显示任何内容

这是准备好的语句之前的代码

$aproved='1';        
$conn = new mysqli(...);     

 $sql = "SELECT * FROM tda WHERE aproved = '$aproved'";
$result = mysqli_query($conn, $sql);
$queryResults = mysqli_num_rows($result);

if($queryResults > 0)
{

while ($row = mysqli_fetch_assoc($result)) 
 {

 $connection = new mysqli(..);  


 echo "  <li>


      <a href='../reportaje/tda.php?title=".$row['d_title']."&date=".$row['d_dat']."&hmm=".$row['d_id']."'>

        ".$row['d_title']."

         </a>
         </li>";

这是带有预准备语句的代码，但它不起作用

   $aproved='1';   

$mysqli = new mysqli(...);     
 $stmt = $mysqli->prepare("SELECT * FROM myTable WHERE name = ?");
$stmt->bind_param("tda", $aproved);
$stmt->execute();

 $result = $stmt->get_result();
if($result->num_rows === 0) 
exit('No rows');


 while($row = $result->fetch_assoc())
{

   echo "  <li>


         <a href='../reportaje/tda.php?title=".$row['d_title']."&date=".$row['d_dat']."&hmm=".$row['d_id']."'>            
           ".$row['d_title']."
         </a>
         </li>";

}
   $stmt->close();

并且我没有任何错误

Answer 1

您有一些翻译无法确定其来源，但应该更像是...

return trackPath.copy(strokingWithWidth: 6, lineCap: CGLineCap.round, lineJoin: CGLineJoin.round, miterLimit: 10) as! CGMutablePath

bind_param()将绑定的数据类型作为第一个参数。

还将表名从$stmt = $mysqli->prepare("SELECT * FROM tda WHERE aproved = ?"); $stmt->bind_param("s", $aproved); $stmt->execute();移回SQL语句，并调整搜索的字段名。

使用准备好的语句方法进行查询的问题

1 个答案: