Question

我需要从response=列表中获得多个随机答复，而不能重复。

因此，当有人输入!pick时，机器人会从responses list中随机选择。

example like Quiz top rank 1, 2, 3 and 4 to 10 :
when used `!pick` command

bot reply's 
Top 1 'Eagle'
Top 2 'Apple'
Top 3 'Elephant'
Top 4 'Cat'
Top 5 'Bear'
Top 6 'Snake'
Top 7 'Deer'
Top 8 'Rhino'
Top 9 'Crocodile'
Top 10 'Lion'

更新

responses = [(60, ("One", "Five", "Seven")), (30, ("Two", "Four", "Six")), (10, ("Three", "Eight"))]
total = sum(w for w, vals in responses)
vals, weights = zip(*[(val, (w/len(vals))/total) for w, vals in responses for val in vals])

@bot.command(pass_context=True)  
async def pick(k : int):
    chosen = choice(vals, size=8, replace=False, p=weights)
    a, b, c = chosen[:2], chosen[:2], chosen[:4]
    embed = discord.Embed(description='\n'.join(b))
    await bot.say(embed=embed)

Answer 1

random.choices可以列出一个权重列表。

responses = [(60, ("One", "Five", "Seven")), (30, ("Two", "Four", "Six")), (10, ("Three", "Eight"))]
vals, weights = zip(*[(val, w/len(vals)) for w, vals in responses for val in vals])

@bot.command()  
async def pick(k : int):
    if 0 <= k <= 10:
        embed = discord.Embed(description='\n'.join(random.choices(vals, weights=weights, k=k)))
        await bot.say(embed=embed)

这是使用numpy.random.choice

的版本

responses = [(60, ("One", "Five", "Seven")), (30, ("Two", "Four", "Six")), (10, ("Three", "Eight"))]
total = sum(w for w, vals in responses)
vals, weights = zip(*[(val, (w/len(vals))/total) for w, vals in responses for val in vals])

@bot.command(pass_context=True)  
async def pick(k : int):
    for x in zip(*[iter(choice(vals, size=6, replace=False, p=weights))]*2):
        embed = discord.Embed(description='\n'.join(x))
        await bot.say(embed=embed)

这是a，b，c版本：

@bot.command(pass_context=True)  
async def pick(k : int):
    chosen = choice(vals, size=8, replace=False, p=weights)
    a, b, c = chosen[:2], chosen[2:4], chosen[4:]
    for x in (a, b, c): 
        embed = discord.Embed(description='\n'.join(x))
        await bot.say(embed=embed)

从列表中按重量获取随机响应

1 个答案: