Question

嗨，我是IOS App开发的新手。我的代码是

func sendRequest<T: Decodable>(api: String, parameters: [String: String]? = nil, outputBlock: @escaping (T) -> () ) {

    guard let url = URL(string: "http://xxyyzz.com/appRegister.php") else {return}

    print("hitting : -", url.absoluteString)

    var request = URLRequest(url: url)

    request.httpMethod = "POST"

    request.addValue("application/json", forHTTPHeaderField: "Content-Type")

    request.addValue("application/json", forHTTPHeaderField: "Accept")

    let newparam = ["name": "rr", "pass": "123456", "email": "rr@rr.com", "passConfirm":"123456"]

    let httpBody = try? JSONSerialization.data(withJSONObject: newparam)

    request.httpBody = httpBody

    if let data = request.httpBody, let str = String(data: data, encoding: String.Encoding.utf8) {

        print(str)

    }

    URLSession.shared.dataTask(with: request as URLRequest) { (data, response, error) in

        DispatchQueue.main.async {

            Indicator.shared.hideProgressView()

            if let err = error {

                print(err.localizedDescription)

                return

            }

            guard let data = data else {return}

            do {

                let obj = String(data: data, encoding: String.Encoding.utf8)

                print(obj ?? "oberrrrr")

            }

        }

        }.resume()

}

和根据代码显示的控制台打印结果

击中：-http://xxyyzz.com/appRegister.php   {“ email”：“ rr@rr.com”，“ passConfirm”：“ 123456”，“ name”：“ rr”，“ pass”：“ 123456”}

{“错误”：“请输入所有字段。”}

URL和参数在邮递员上效果很好，这意味着我的代码中缺少它们。

Answer 1

仅在其他人遇到此问题时才回答问题。这段代码很好，但是问题出在php web服务上，因为后端开发人员不接受json值作为参数，而是需要发送表单数据。因此，可以在此处进行两种类型的修复

通过添加：-
在后端接受json
$ postdata = file_get_contents（“ php：// input”）; $ request = json_decode（$ postdata，true）;
发送表单数据而不是json
```
-PassThru -AsCustomObject -Force
```
}

urlrequest未发送发布请求

1 个答案: