带有超时和shell = True的python27'subprocess'

Question

这是Python代码，用于在超时的情况下运行给定命令并返回其stdout

def run_python2_file_with_args(*args, **kwargs):
    timeout = kwargs.pop('timeout', 500)
    from subprocess import Popen, PIPE
    from threading import Timer

    cmd = ' '.join(str(arg) for arg in args)
    print(cmd)
    proc = Popen(cmd, stdout=PIPE, stderr=PIPE)
    print(timeout)
    timer = Timer(timeout, proc.kill)
    try:
        timer.start()
        stdout, stderr = proc.communicate()
    finally:
        timer.cancel()
    print(stdout)

这对于超时工作正常，但是如果在Popen计时器中使用“ shell = True”，超时后不会终止进程。有人可以帮我吗