Question

我有一项家庭作业，要求我检查列表中的每个单词是否包含特定字母，并告诉用户列表中有多少个单词包含该字母。下面是我的代码：

letterSearch = input("Please enter a letter to search for: ")

w = ['', '', '', '']
w[0] = input("Please enter up to 4 words: ")
w[1] = input(": ")
w[2] = input(": ")
w[3] = input(": ")

first = 0
second = 0
third = 0
fourth = 0

for ch in w[0]:
    if ch is letterSearch:
        first = 1
for ch in w[1]:
    if ch is letterSearch:
        second = 1
for ch in w[2]:
    if ch is letterSearch:
        third = 1
for ch in w[3]:
    if ch is letterSearch:
        fourth = 1

ans = first + second + third + fourth

print(ans, "of the entered words contain the letter", letterSearch)

我遇到的问题是，在作业中，教授希望用户能够输入单词直到按下回车键，而我将可以输入的最大单词数设置为4。一种方法，使用户能够输入任意数量的单词，而单词仍在列表中分开，直到按下回车键？

Answer 1

以单个字符串读取整个输入，然后使用split将其分解为单词列表。

Answer 2

您可以在字符串上使用split将其分成几部分。只需要求您的用户用一些字符分隔提供给input的单词：空格是一种方便的字符。然后，您可以根据输入的字符串创建一个列表，然后继续进行其余的分配工作。

>>> w = input("Please enter words separated by spaces:")
Please enter words separated by spaces:one two three four five six
>>> w
'one two three four five six'
>>> w_list = w.split(" ")
>>> w_list
['one', 'two', 'three', 'four', 'five', 'six']

Answer 3

要使用任意数量的单词分割字符串（假设它们由空格分隔），请使用内置的.split()函数，如下所示：

my_str = "this sentence has some words"
print(my_str.split())

>>> ['this', 'sentence', 'has', 'some', 'words']

除此之外，您的代码还存在一些分解问题。鉴于您不知道单词的数量，因此您无法手动在每个单词中搜索字母。最好遍历拼接词的列表：

letter_search = input("Please enter a letter to search for: ")

words = input("Please enter some words: ")
words = words.split()

in_word_count = 0

# Go through the list of words;
for word in words:
    # Check if the letter specified is in the word
    if letter_search in word:
        # Increment the count
        in_word_count += 1

print(in_word_count, "of the entered words contain the letter", letter_search)

用户如何在按下Enter键之前逐行输入单词？

3 个答案: