Question

我想获取我的计算机的IP地址。我的整个代码是

<?php

   echo $_SERVER['REMOTE_ADDR'];

当我尝试在终端php -f index.php中运行文件时，出现此错误PHP Notice: Undefined index: HTTP_X_FORWARDED_FOR in /home/orpheus/Practice_dev/requestMicroservice/index.php on line 4

我也在网站上找到了此代码，并认为该代码可以获取我的IP地址

function get_ip() {
  //Just get the headers if we can or else use the SERVER global.
  if ( function_exists( 'apache_request_headers' ) ) {
    $headers = apache_request_headers();
  } else {
    $headers = $_SERVER;
  }
  //Get the forwarded IP if it exists.
  if ( array_key_exists( 'X-Forwarded-For', $headers ) && filter_var( $headers['X-Forwarded-For'], FILTER_VALIDATE_IP, FILTER_FLAG_IPV4 ) ) {
    $the_ip = $headers['X-Forwarded-For'];
  } elseif ( array_key_exists( 'HTTP_X_FORWARDED_FOR', $headers ) && filter_var( $headers['HTTP_X_FORWARDED_FOR'], FILTER_VALIDATE_IP, FILTER_FLAG_IPV4 ) ) {
    $the_ip = $headers['HTTP_X_FORWARDED_FOR'];
  } else {

    $the_ip = filter_var( $_SERVER['REMOTE_ADDR'], FILTER_VALIDATE_IP, FILTER_FLAG_IPV4 );
  }
  return $the_ip;
}

但是当我在终端中运行文件时，会得到未定义的索引：REMOTE_ADDR。

我在做什么错？

回声$ _SERVER ['REMOTE_ADDR'];显示未定义

0 个答案: