Question

我正在编写一个基本的老虎机代码，并且在程序运行时似乎陷入了无限循环。如果有人可以弄清楚该错误的出处或建议的方法。感谢所有帮助。

public class Java_Lab_3 {
    public static void main(String[] args) {
        int endgame;  
        int slot1;
        int slot2;
        int slot3;

        Random rand =  new Random();
        Scanner keyboard = new Scanner(System.in);  

        System.out.println("Want to test your luck?");
        System.out.println("To Spin, type any positive number");
        System.out.println("To End Game, type -1 and press enter ");

        endgame = keyboard.nextInt();

        while (endgame != -1) {
            slot1 = rand.nextInt(10);
            slot2 = rand.nextInt(10);
            slot3 = rand.nextInt(10);

            System.out.println(slot1 + slot2 + slot3);
            System.out.println(endgame);

            if (slot1 == slot2 && slot1 == slot3) { // Then they have JACKPOT
                System.out.println("You've Won!");
            } else if (slot1 == slot2 || slot2 == slot3 || slot1 == slot3) { // They MATCHED 2
               System.out.println("We have twins... You've matched a pair!");
            } else {
                System.out.println("Sucks to Suck, don't quit your day job!");
            }
        }
    }
}

Answer 1

如果您想退出该循环，则必须对退出条件的可能性进行编程。例如...

while (endgame != -1) {
    System.out.print("Do you want to play again? (-1 to quit): ");
    endgame = keyboard.nextInt();
}

通过这种方式，您提示用户每次滚动后再次播放。

Answer 2

您应该将endgame = keyboard.nextInt();放到里面。并为其分配一些值（出于安全性考虑）

编辑：添加计数器功能

    int endgame = 1;  
    int count1 = 0;
    while (endgame != -1) {
        endgame = keyboard.nextInt();
        slot1 = rand.nextInt(10);
        slot2 = rand.nextInt(10);
        slot3 = rand.nextInt(10);

        System.out.println(slot1 + slot2 + slot3);
        count1++;
        System.out.println(count1); //replace here

        if (slot1 == slot2 && slot1 == slot3) { // Then they have JACKPOT
            System.out.println("You've Won!");
        } else if (slot1 == slot2 || slot2 == slot3 || slot1 == slot3) { // They MATCHED 2
           System.out.println("We have twins... You've matched a pair!");
        } else {
            System.out.println("Sucks to Suck, don't quit your day job!");
        }
    }

Answer 3

修改后的代码，在while循环内移动了用户提示：

public class Java_Lab_3 {
    public static void main(String[] args) {
        int endgame = 0;  
        int slot1;
        int slot2;
        int slot3;

        Random rand =  new Random();
        Scanner keyboard = new Scanner(System.in);  

        while (endgame != -1) {
            System.out.println("Want to test your luck?");
            System.out.println("To Spin, type any positive number");
            System.out.println("To End Game, type -1 and press enter ");

           endgame = keyboard.nextInt();

            slot1 = rand.nextInt(10);
            slot2 = rand.nextInt(10);
            slot3 = rand.nextInt(10);

            System.out.println(slot1 + slot2 + slot3);
            System.out.println(endgame);

            if (slot1 == slot2 && slot1 == slot3) { // Then they have JACKPOT
                System.out.println("You've Won!");
            } else if (slot1 == slot2 || slot2 == slot3 || slot1 == slot3) { // They MATCHED 2
               System.out.println("We have twins... You've matched a pair!");
            } else {
                System.out.println("Sucks to Suck, don't quit your day job!");
            }
        }
    }
}

JAVA中的老虎机无限循环故障

3 个答案: