Question

当用户触摸视图时，我想检测JUST双击/单击。

我做了这样的事情：

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event 
{
    UITouch *touch = [touches anyObject];
    CGPoint prevLoc = [touch ]
    if(touch.tapCount == 2)
        NSLog(@"tapCount 2");
    else if(touch.tapCount == 1)
        NSLog(@"tapCount 1");
}

但它总是在2次点击之前检测到1次点击。我怎样才能检测到1/2水龙头？

Answer 1

谢谢你的帮助。我也找到了这样的方式：

-(void)handleSingleTap
{
    NSLog(@"tapCount 1");
}

-(void)handleDoubleTap
{
    NSLog(@"tapCount 2");
}

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event
{
    NSUInteger numTaps = [[touches anyObject] tapCount];
    float delay = 0.2;
    if (numTaps < 2) 
    {
        [self performSelector:@selector(handleSingleTap) withObject:nil afterDelay:delay ];     
        [self.nextResponder touchesEnded:touches withEvent:event];
    } 
    else if(numTaps == 2) 
    {
        [NSObject cancelPreviousPerformRequestsWithTarget:self];            
        [self performSelector:@selector(handleDoubleTap) withObject:nil afterDelay:delay ];
    }               
}

Answer 2

这将有助于定义单击和双击的方法

(void) handleSingleTap {}
(void) handleDoubleTap {}

那么在touchesEnded中你可以根据点击次数调用适当的方法，但只能在延迟后调用handleSingleTap以确保没有执行双击：

-(void) touchesEnded(NSSet *)touches withEvent:(UIEvent *)event {
  if ([touch tapCount] == 1) {
        [self performSelector:@selector(handleSingleTap) withObject:nil
           afterDelay:0.3]; //delay of 0.3 seconds
    } else if([touch tapCount] == 2) {
        [self handleDoubleTap];
    }
}

在touchesBegan中，取消对handleSingleTap的所有请求，以便第二次点击取消第一次点击对handleSingleTap的通话，只会调用handleDoubleTap

[NSObject cancelPreviousPerformRequestsWithTarget:self
  selector:@selector(handleSingleTap) object:nil];

Answer 3

也许你可以使用一些时间间隔。等待事件调度（x）ms。如果您在该时间段内获得两次点击，请拨打双击。如果您只获得一次调度。

使用UIViews只检测双击或单击？

3 个答案: