Question

我有2张桌子：

___房间

|--------|------------|
| ROO_Id | ROO_Number |
|--------|------------|
| 22     | 101        |
| 23     | 102        |
| 24     | 201        |
|--------|------------|

___预订

|--------|------------|------------|------------|-------------------|
| BOO_Id | BOO_RoomId | BOO_DateCI | BOO_DateCO | BOO_ArrivalStatus |
|--------|------------|------------|------------|-------------------|
| 34     | 22         | 2018-07-17 | 2018-07-20 | checkin           |
| 35     | 23         | 2018-07-17 | 2018-07-18 | checkout          |
| 36     | 24         | 2018-07-19 | 2018-07-21 | none              | 
| 37     | 23         | 2018-07-18 | 2018-07-21 | none              | 
|--------|------------|------------|------------|-------------------|

我的目标是提供以下报告：

报告日期为今天2018-07-18。

|------------|----------------|-------------------|
| ROO_Number | BOO_LiveStatus | BOO_ArrivalStatus |
|------------|----------------|-------------------|
| 101        | in-house       | checkin           |
| 102        | none           | no                |
| 201        | none           | no                |
|------------|----------------|-------------------|

我在这里放了一个SQLFidde： http://sqlfiddle.com/#!9/bb6a30/4

实际上，我距离很近，但是我有一个小问题。

每个房间只需要排一行。对于102号房，我有两次连续的预订，查询返回两行，而它应该返回the booking with the higher id (BOO_Id)。

我最后一次尝试是这样：

SELECT 
    ROO_Id,
    IF(BOO_DateCI <= '2018-07-18' AND BOO_DateCO >= '2018-07-18', "in-house", "no")
        AS BOO_LiveStatus,
    IFNULL(BOO_ArrivalStatus, "0") 
        AS BOO_ArrivalStatus,
    BOO_Id,
FROM ___Rooms
LEFT JOIN ___Bookings
    ON ___Rooms.ROO_id = ___Bookings.BOO_RoomId 
        AND '2018-07-18' BETWEEN ___Bookings.BOO_DateCI AND ___Bookings.BOO_DateCO
WHERE ROO_Status != 'inactive'
ORDER BY 
  ROO_Number

能请你帮我吗？

非常感谢。

Answer 1

您应该通过BOO_RoomId在max（BOO_DateCI）组上添加内部联接

  SELECT 
    ROO_Id,
    IF(BOO_DateCI <= '2018-07-18' AND BOO_DateCO >= '2018-07-18', "in-house", "no")
        AS BOO_LiveStatus,
    IFNULL(BOO_ArrivalStatus, "0") 
        AS BOO_ArrivalStatus,
    BOO_Id
FROM ___Rooms
inner join  (
  select  BOO_RoomId,max(BOO_DateCI) max_BOO_DateCI
  from ___Bookings
  group by BOO_RoomId

) t on t.BOO_RoomId = ___Rooms.ROO_id 
LEFT JOIN ___Bookings
    ON ___Rooms.ROO_id = ___Bookings.BOO_RoomId 
        AND '2018-07-18' BETWEEN ___Bookings.BOO_DateCI AND ___Bookings.BOO_DateCO
        AND t.max_BOO_DateCI=  ___Bookings.BOO_DateCI
ORDER BY 
  ROO_Number

仅从MySQL查询返回较高的ID

1 个答案: