Question

我有这个数组（摘要）

array (size=631)
  0 => string '11:27:35.750 INFO - Selenium build info: version: '3.4.0', revision: 'unknown'
' (length=80)
  1 => string '11:27:35.751 INFO - Launching a standalone Selenium Server
' (length=60)
  2 => string '2018-07-17 11:27:35.785:INFO::main: Logging initialized @534ms to org.seleniumhq.jetty9.util.log.StdErrLog
' (length=108)
  3 => string '11:27:35.890 INFO - Driver class not found: com.opera.core.systems.OperaDriver
' (length=80)
  4 => string '11:27:35.891 INFO - Driver provider com.opera.core.systems.OperaDriver registration is skipped:
' (length=97)
  5 => string 'Unable to create new instances on this machine.
' (length=49)
  6 => string '11:27:35.891 INFO - Driver class not found: com.opera.core.systems.OperaDriver
' (length=80)
  7 => string '11:27:35.891 INFO - Driver provider com.opera.core.systems.OperaDriver is not registered
' (length=90)
  8 => string '11:27:35.893 INFO - Driver provider org.openqa.selenium.safari.SafariDriver registration is skipped:
' (length=102)
  9 => string ' registration capabilities Capabilities [{browserName=safari, version=, platform=MAC}] does not match the current platform WIN10
' (length=130)
  10 => string '2018-07-17 11:27:35.966:INFO:osjs.Server:main: jetty-9.4.3.v20170317

是否有一个内置函数按其索引对数组进行排序，以使索引pos 0的内容为10，反之亦然？

还是我必须自己写？

Answer 1

您似乎正在寻找array_reverse

<?php
$input  = array("php", 4.0, array("green", "red"));
$reversed = array_reverse($input);
$preserved = array_reverse($input, true);

print_r($input);
print_r($reversed);
print_r($preserved);
?>

输出：

Array
(
    [0] => php
    [1] => 4
    [2] => Array
        (
            [0] => green
            [1] => red
        )

)
Array
(
    [0] => Array
        (
            [0] => green
            [1] => red
        )

    [1] => 4
    [2] => php
)
Array
(
    [2] => Array
        (
            [0] => green
            [1] => red
        )

    [1] => 4
    [0] => php
)

Answer 2

好的，我找到了解决方案。我必须使用功能array_reverse

PHP-按索引对数组排序

2 个答案: