Question

我正在尝试在Azure Logic App中调用存储过程。但是，每当我尝试连接到数据库和选择过程或执行应用程序时，都会出现以下错误。

`

{
  "status": 400,
  "message": "Can not add property StartTime to Newtonsoft.Json.Linq.JObject. Property with the same name already exists on object.\r\nclientRequestId: 99825289-bbe8-4b91-8323-075e8cacd09c",
  "source": "sql-logic-cp-centralindia.logic-ase-centralindia.p.azurewebsites.net"
}

`

如果尝试执行SQL选择查询而不是存储过程，则会遇到相同的错误。

这是逻辑应用程序的代码。有什么建议么？

`

{
  "$connections": {
    "value": {
      "sql": {
        "connectionId": "/subscriptions/XXXX/resourceGroups/Reports/providers/Microsoft.Web/connections/sql",
        "connectionName": "sql",
        "id": "/subscriptions/XXXX/providers/Microsoft.Web/locations/centralindia/managedApis/sql"
      }
    }
  },
  "definition": {
    "$schema": "https://schema.management.azure.com/providers/Microsoft.Logic/schemas/2016-06-01/workflowdefinition.json#",
    "actions": {
      "Execute_stored_procedure": {
        "inputs": {
          "host": {
            "connection": {
              "name": "@parameters('$connections')['sql']['connectionId']"
            }
          },
          "method": "post",
          "path": "/datasets/default/procedures/@{encodeURIComponent(encodeURIComponent('[dbo].[SchoolDataDump]'))}"
        },
        "runAfter": {},
        "type": "ApiConnection"
      },
      "Response": {
        "inputs": {
          "statusCode": 200
        },
        "kind": "http",
        "runAfter": {
          "Execute_stored_procedure": [
            "Succeeded"
          ]
        },
        "type": "Response"
      }
    },
    "contentVersion": "1.0.0.0",
    "outputs": {},
    "parameters": {
      "$connections": {
        "defaultValue": {},
        "type": "Object"
      }
    },
    "triggers": {
      "manual": {
        "inputs": {
          "schema": {}
        },
        "kind": "Http",
        "type": "Request"
      }
    }
  }
}

`

Answer 1

好的，那是一个棘手的错误。经过一番挣扎，我得以弄清楚这个问题。在我的选择查询中，我有两个名称相同的字段。这导致创建输出JSON时出现问题。

我在查询中有两个字段，如下所示

Select .. SM.StartTime,... SS.StartTime from tables .. joins

SQL输出在SQL输出中具有StartTime的两倍。因此，我添加了一个别名，如下所示，它解决了该问题。

Select .. SM.StartTime,... SS.StartTime as SessionStartTime from tables .. joins

Azure LogicApp无法通过SQL连接

1 个答案: