Question

实际上，我正在尝试使用Retrofit将txt文件发送到服务器。但是当我实际尝试发送它时，它从onFailure方法中给我以下错误

我是android的新手，通过查看一些改装指南，我仍然无法理解我做错了什么，即使我以正确的方式使用改装，如果有人能够帮帮我。

E / TAG：无法将帖子提交到API。

但是实际上它是在服务器上创建一个文件夹但没有发送文件，我在做什么错了？

这是我的ApiUtils.java

import okhttp3.RequestBody;
import retrofit2.Call;
import retrofit2.http.Body;
import retrofit2.http.POST;

public interface APIService {

    @POST("UPD.aspx?CART=PTERM")
    Call<MyResponse> savePost(@Body RequestBody text);
}

这里是RetrofitClient.java

import retrofit2.Retrofit;
import retrofit2.converter.gson.GsonConverterFactory;

public class RetrofitClient {

    private static Retrofit retrofit = null;

    public static Retrofit getClient(String baseUrl) {
        if (retrofit==null) {
            retrofit = new Retrofit.Builder()
                    .baseUrl(baseUrl)
                    .addConverterFactory(GsonConverterFactory.create())
                    .build();
        }
        return retrofit;
    }
}

这是APIService.java

import okhttp3.MultipartBody;
import retrofit2.Call;
import retrofit2.http.Multipart;
import retrofit2.http.POST;
import retrofit2.http.Part;

public interface APIService {

    @Multipart
    @POST("UPD.aspx?CART=PTERM")
    Call<Void> savePost(@Part MultipartBody.Part text);
}

这里是sendPost（）方法，我用来通过onClick发送文件

public void sendPost() {
    File file = new File("/data/data/com.example.igardini.visualposmobile/files/scontrino.txt");

    MultipartBody.Builder builder = new MultipartBody.Builder();
    builder.setType(MultipartBody.FORM);

    builder.addFormDataPart("scontrino", file.getName());

    MultipartBody requestBody = builder.build();

    APIService apiService = ApiUtils.getAPIService();

    Call<Void> call = apiService.savePost(requestBody);

    call.enqueue(new Callback<Void>() {
        @Override
        public void onResponse(Call<Void> call, Response<Void> response) {
            if (response.isSuccessful()) {

            } else {

            }
        }

        @Override
        public void onFailure(Call<Void> call, Throwable t) {
            Log.e("TAG", t.toString());
        }
    });
}

如果有人会建议我如何通过http请求改进改版的性能，我将不胜感激。

Answer 1

使用Void代替空类

public void sendPost(MultipartBody.Part txt) {
mAPIService.savePost(txt).enqueue(new Callback<Void>() {
    @Override
    public void onResponse(Call<Void> call, Response<Void> response) {

        if(response.isSuccessful()) {
            Log.i("TAG", "post submitted to API." + response.body().toString());
        }
    }

    @Override
    public void onFailure(Call<Void> call, Throwable t) {
        Log.e("TAG", "Unable to submit post to API.");
    }
});
}

Request body

RequestBody fbody = RequestBody.create(MediaType.parse("text/*"), file); 
builder.addFormDataPart("scontrino", file.getName(),fbody);

Answer 2

private void sendPost（）{

    MultipartBody.Builder builder = new MultipartBody.Builder();
    builder.setType(MultipartBody.FORM);

    builder.addFormDataPart("scontrino", file.getName());

    MultipartBody requestBody = builder.build();

    MainInterface apiService = ApiClient.getClient().create(MainInterface.class);

    Call<MyResponse> call = apiService.savePost(requestBody);

    call.enqueue(new Callback<MyResponse>() {
        @Override
        public void onResponse(Call<MyResponse> call, Response<MyResponse> response) {
            progressBarHandler.dismiss();
            if (response.isSuccessful()) {

            } else {

            }
        }

        @Override
        public void onFailure(Call<MyResponse> call, Throwable t) {

        }
    });
}

无法将帖子提交到API改装

2 个答案: