ORA-01427：单行子查询返回多行-问题

Question

update dsalesinvoicehdr set paymentterms = ( select pt.termcode from dsalesinvoicehdr dsh
       inner join mg_subledger mp on mp.mg_subledgerid = dsh.customer 
       inner join mg_partytbill mb on mb.bsubledger = mp.subledgercode  
       left join payterm pt on pt.paytermid = mb.paymentterm)

  

ORA-01427：单行子查询返回多个行

如何解决此问题。请帮助

Answer 1

将导致此错误，因为您的子查询返回了多条信息您的子查询返回了多行数据

您可以使用UPDATE和JOIN

update
( 
select pt.termcode,dsh.paymentterms 
from dsalesinvoicehdr dsh
inner join mg_subledger mp on mp.mg_subledgerid = dsh.customer 
inner join mg_partytbill mb on mb.bsubledger = mp.subledgercode  
left join payterm pt on pt.paytermid = mb.paymentterm
) t
set  t.termcode= t.paymentterms  

Answer 2

使用更新并加入队友！

update
( 
   select pt.termcode,dsh.paymentterms 
   from dsalesinvoicehdr dsh
   inner join mg_subledger mp on mp.mg_subledgerid = dsh.customer 
   inner join mg_partytbill mb on mb.bsubledger = mp.subledgercode  
   left join payterm pt on pt.paytermid = mb.paymentterm
) tab
set  tab.termcode= tab.paymentterms 

Answer 3

您需要选择一个值。常见的方法是聚合函数或where rownum = 1：

update dsalesinvoicehdr
    set paymentterms = (select pt.termcode
                        from dsalesinvoicehdr dsh inner join
                             mg_subledger mp
                             on mp.mg_subledgerid = dsh.customer inner join
                             mg_partytbill mb
                             on mb.bsubledger = mp.subledgercode join
                             payterm pt
                             on pt.paytermid = mb.paymentterm
                        where rownum = 1
                       );

子查询中不需要left join。无论如何，不​​匹配将导致NULL。