Question

我正在用Python 3写一个Discord机器人，希望将URL从http / https转换为Steam。

例如，类似

https://store.steampowered.com/app/286160/

将成为

steam://store/286160

是否有一种简单的方法可以轻松添加到其中？

Answer 1

只需使用简单的split

>>> "steam://store/"+url.split("/")[-2]

>>> url = "https://store.steampowered.com/app/286160/"
>>> steam_url = "steam://store/"+url.split("/")[-2]
>>> print steam_url
steam://store/286160
>>>

Answer 2

@Andrew ，您也可以尝试以下方法。

>>> inp = "https://store.steampowered.com/app/286160/"
>>>
>>> inp_url = "https://store.steampowered.com/app/286160/"
>>> arr = inp_url.split('://')
>>> arr
['https', 'store.steampowered.com/app/286160/']
>>>
>>> domain = arr[1].split('.')
>>> domain
['store', 'steampowered', 'com/app/286160/']
>>>
>>> sub_url = domain[-1].split('/')[-2]
>>> sub_url
'286160'
>>>
>>> out_url = 'stream://' + domain[0] + '/' + sub_url + '/'
>>> out_url
'stream://store/286160/'
>>>

最后，您可以设计以下函数来将实现的代码重用于url数量。

Python代码

def get_modified_url(inp_url, protocol='stream'):
    arr = inp_url.split('://')[1].split('.')
    sub_url1 = arr[0]
    sub_url2 = arr[-1].split('/')[-2]
    out_url = protocol + '://' + '/'.join([sub_url1, sub_url2])

    return out_url

if __name__ == '__main__':
    # INPUT 1 (Use default protocol as stream)
    url = 'https://store.steampowered.com/app/286160/'
    output = get_modified_url(url)
    print output

    # INPUT 2 (Override default protocol)
    url2 = 'https://store.steampowered.com/app/286560/'
    output2 = get_modified_url(url2, 'new_stream')
    print output2

    # INPUT 3 (Override default protocol)
    url3 = 'https://the_store2.steampowered.com/app/286161/'
    output3 = get_modified_url(url3, 'new_stream')
    print output3

输出

stream://store/286160
new_stream://store/286560
new_stream://the_store2/286161

Answer 3

您可以像这样在Python中使用re来拆分URL。

import re

url = 'https://store.steampowered.com/app/286160/'

new_url = 'steam://store/' + re.split('/', url)[-2]

print(new_url) # output - steam://store/286160

Answer 4

from urllib.parse import urlparse
url = "https://store.steampowered.com/app/286160/"
o = urlparse(url)

a = url.split(".")[0] 

b = url.split("/")[-2]

c = a.replace(o.scheme,"steam")

print(c + "/" + b)

用令牌值替换Python字符串

4 个答案:

Python代码

输出