Question

我刚接触PHP，我想制作一个简单的数据查找脚本。这是我现在在index.php文件中使用的代码。

<?php
    $mysqlHost = 'localhost';
    $mysqlUser = 'root';
    $mysqlPass = 'password';
    $mysqlDatabase = 'core';

    $conn = new mysqli($mysqlHost, $mysqlUser, $mysqlPass, $mysqlDatabase);
    if ($conn -> connect_error)
        die('Connection Failed: ' . $conn -> connect_error);

    $sql = 'SELECT * FROM users WHERE name = SimonM34';
    $result = $conn -> query($sql);

    if ($result -> num_rows > 0) {
        $row = $result -> fetch_assoc();
        $rawJson -> name = $row['name'];
        $rawJson -> rank = $row['rank'];
        $rawJson -> subrank = $row['subrank'];
        $rawJson -> balance = $row['balance'];
        $json = json_encode($rawJson);
        echo $json;
    } else {
        echo 'No users found!';
    }

    $conn -> close();

?>

这总是显示No users found，但是如果我将语句更改为SELECT * FROM users，它将返回{"name":"SimonM34","rank":"Guest","subrank":"None","balance":"500"}，这很奇怪，我无法弄清楚为什么会发生这种情况。

谢谢

Answer 1

问题出在您的查询中：

$sql = 'SELECT * FROM users WHERE name = SimonM34';

您正在比较不带引号的字符串值。用以下内容替换您的查询：

$sql = 'SELECT * FROM users WHERE name = "SimonM34"';

那是我唯一的问题。

MySQL在表中找不到特定的行

1 个答案: