Question

我有一个Web服务，想在我的WebService API链接中通过Flutter Dart json发布数据

Answer 1

您需要进一步说明API和要发送的内容。这是HTTP client library

中的一个简单示例

import 'package:http/http.dart' as http;

var url = "http://example.com/whatsit/create";
http.post(url, body: {"name": "doodle", "color": "blue"})
    .then((response) {
  print("Response status: ${response.statusCode}");
  print("Response body: ${response.body}");
});

http.read("http://example.com/foobar.txt").then(print);

Answer 2

能否请您提供有关API的更多详细信息？

假设您的API像这样http://localhost:3000

您可以按照以下要求进行请求

  Future<String> create(String text) async {
    HttpClient client = new HttpClient();
    try {
      HttpClientRequest req = await client.post('localhost', 3000, '/');
      req.headers.contentType = new ContentType("application", "json", charset: "utf-8");
      req.write('{"key":"value"}');
      HttpClientResponse res = await req.close();
      if (res.statusCode == HttpStatus.CREATED) return await res.transform(UTF8.decoder).join();
      else throw('Http Error: ${res.statusCode}');
    } catch (exception) {
      throw(exception.toString());
    }
}

OR

如果您想发布一个Map（通过您拥有的json创建），则可以使用http包。 https://pub.dartlang.org/packages/http

将“ package：http / http.dart”导入为http；

String url = "http://example.com/whatsit/create";
http.post(url, body: {"name": "doodle", "color": "blue"})
    .then((response) {
  print("Response status: ${response.statusCode}");
  print("Response body: ${response.body}");
});

Answer 3

我建议使用此软件包dio package

发布帖子会像这样：

Future<List> postDataFromURL_list(String url, Map map) async {
    // TODO: implement postDataFromURL_list
    Response response;
    Dio dio = new Dio();
    FormData formData = new FormData.from(map);

    response = await dio.post(url, data: formData);

  }

Answer 4

对于REST API调用，我更喜欢使用名为Dio的库。使用Dio进行GET，POST，PUT，DELETE等调用的方法太简单了。

例如

import 'package:dio/dio.dart';

   //Now like this

void _makeApiCall() async {
   Dio dio = new Dio();
   Response apiResponse = await dio.get('${YOUR URL}?id=$id'); //Where id is just a parameter in GET api call
   print(apiResponse.data.toString());
}

如果您要进行POST调用，并且需要发送表单数据，就像这样

void _makeApiCall() async {
   Dio dio = new Dio();
   FormData formData = FromData.from({
    name : "name",
    password: "your password",
   }); // where name and password are api parameters
   Response apiResponse = await dio.post('${YOUR URL}', data: formData); 
   print(apiResponse.data.toString());
}

此外，您可以将接收到的数据映射到所谓的POJO中，以更好地处理和使用。如果您想知道如何将数据映射到POJO（对象）中，请告诉我。

如何使用方法和数据发布到外部API

4 个答案: