Question

我正在iPhone中使用XMPP Framework创建聊天应用程序。我想知道发送和接收消息的过程。任何人都可以给我一个解决方案吗？

提前致谢。

Answer 1

下载XMPPFramework并解压缩。里面有几个文件夹。打开'Xcode'文件夹＆gt;打开'iPhoneXMPP'文件夹＆gt;点击“iPhoneXMPP.xcodeproj”＆gt;运行。它首先要求登录凭证。成功登录后，它将显示您的好友列表。它适用于Gmail。每个传入消息都有一个回调方法：

- (void)xmppStream:(XMPPStream *)sender didReceiveMessage:(XMPPMessage *)message
{
    user = [xmppRosterStorage userForJID:[message from] xmppStream:sender     managedObjectContext:[self managedObjectContext_roster]];

    if ([message isChatMessageWithBody])
    {
        NSString *body = [[message elementForName:@"body"] stringValue];
    NSString *from = [[message attributeForName:@"from"] stringValue];
        NSMutableDictionary *m = [[NSMutableDictionary alloc] init];
        [m setObject:body forKey:@"msg"];
        [m setObject:from forKey:@"sender"];

        if ([[UIApplication sharedApplication] applicationState] == UIApplicationStateActive)
        {          
             NSLog(@"Applications are in active state");
             //send the above dictionary where ever you want
        }
        else
        {
            NSLog(@"Applications are in Inactive state");
            UILocalNotification *localNotification = [[UILocalNotification alloc] init];
            localNotification.alertAction = @"Ok";
            localNotification.applicationIconBadgeNumber=count;
            localNotification.alertBody =[NSString stringWithFormat:@"From:"%@\n\n%@",from,body];
            [[UIApplication sharedApplication] presentLocalNotificationNow:localNotification];
             //send the above dictionary where ever you want
        }
    }
}

对于发送消息，我们必须在任何地方编写我们自己的方法：

-(void)sendMessage
{
    NSString *messageStr =messageField.text;

    if([messageStr length] > 0)
    {              
        NSLog(@"Message sending fron Gmail");
        NSXMLElement *body = [NSXMLElement elementWithName:@"body"];
        [body setStringValue:messageStr];
        NSXMLElement *message = [NSXMLElement elementWithName:@"message"];
        [message addAttributeWithName:@"type" stringValue:@"chat"];
        [message addAttributeWithName:@"to" stringValue:@"destination address"];
        [message addChild:body];
        NSLog(@"message1%@",message);

        [[self appDelegate].xmppSream sendElement:message];
    }    
}

Answer 2

对于在组中发送消息/下面的房间是片段

XMPPMessage *message = [XMPPMessage message];
[message addBody:@"123"];
[self.currentRoom sendMessage:message1]; 

Where self.currentRoom is XMPPRoom

Answer 3

如果您要从Room/Group发送消息，请使用此代码发送消息。

[xmppRoom sendMessage:@"Hi All"];

不需要通过xmppStream发送消息。单行代码对我来说非常适合。

Answer 4

快速谷歌搜索显示许多XMPP libraries，无论是C / C ++还是ObjC。也许http://code.google.com/p/xmppframework/可能是一个很好的起点，虽然我没有亲自尝试过。

Answer 5

以下是通过Swift 3中的XMPPFramework发送消息的解决方案

let user = XMPPJID(string: "user@jabjab.de")
let msg = XMPPMessage(type: "chat", to: user)
msg?.addBody("Message to send")
self.xmppStream.send(msg)

如何使用XMPPFramework发送和接收消息

5 个答案: